Question

我试图通过在网络浏览器中粘贴网址http://127.0.0.1:8000/upload_results/UniEX_HG1_A15来在views.py中调用函数，但是请求失败，并且我看不到为什么我的URL模式不起作用。

错误：

Page not found (404)
Request Method:     GET
Request URL:    http://127.0.0.1:8000/upload_results/UniEX_HG1_A15

Using the URLconf defined in varview.urls, Django tried these URL patterns, in this order:

    ^$ [name='show_index']
    ^admin/
    ^upload/ [name='varview_submission']
    ^upload_results/(?P<project_id>[0-9A-Za-z_]+)/ [name='varview_upload_results']
    ^validate/(?P<project_id>[0-9A-Za-z_]+)/ [name='varview_validate']
    ^filterallprojects/[0-9A-Za-z_]+ [name='varview_filterallprojects']
    ^project/(?P<project_id>[0-9A-Za-z_]+)/wgsmetrics/ [name='varview_wgsmetrics']
    ^project/(?P<project_id>[0-9A-Za-z_]+)/targetgenecoverage/ [name='varview_targetgenecoverage']
    ^project/(?P<project_id>[0-9A-Za-z_]+)/(?P<display_option>[0-9A-Za-z_]+)/ [name='varview_project']
    ^media\/(?P<path>.*)$

The current path, upload_results/UniEX_HG1_A15, didn't match any of these.

这是我的urls.py：

from django.conf import settings
from django.conf.urls import url
from django.conf.urls.static import static
from django.contrib import admin
from varview import views
from varview.forms import DataUploaderForm1, DataUploaderForm2, GetProjectIdForm

urlpatterns = [
    url(r'^$', views.show_index, name='show_index'),
    url(r'^admin/', admin.site.urls),
    url(r'^upload/', views.init_submission, name='varview_submission'),
    url(r'^upload_results/(?P<project_id>[0-9A-Za-z_]+)/', views.upload_results, name='varview_upload_results'), 
]

这已经有一段时间了，但是与此同时我做了很多更改。最新更改是包括芹菜（djcelery）。索引页和其他页面仍然有效。我已经阅读了许多与django-url相关的帖子，但无法弄清楚。

谢谢您的帮助。

Answer 1

请注意，您的网址后有一个斜杠

^upload_results/(?P<project_id>[0-9A-Za-z_]+)/

但是您正在尝试访问不带斜杠的URL

/upload_results/UniEX_HG1_A15

通常，Django将使用斜杠重定向到URL。也许您的MIDDLEWARE设置不正确，或者您已将APPEND_SLASH设置为False。

找不到页面，URL未解析

1 个答案: