Question

我尝试从allshortpath返回的路径中建立新的关系。

$
MATCH (p1:Category {catName: "Main_topic_classifications"}), 
(p2:Category {catName: "Monarchs_of_the_Bulgars"}),
path = allShortestPaths((p2)-[:SUBCAT_OF*]->(p1))

FOREACH (s IN rels(path) | 
  MERGE (startNode(s))-[:NEW_SUBCAT]->(ENDNODE(s)))

但是，当我运行上一个查询时，出现了以下错误：

Neo.ClientError.Statement.SyntaxError: Invalid input '(': expected an identifier character, whitespace, NodeLabel, a property map or ')' (line 5, column 24 (offset: 248))
"      MERGE (:startNode(s))-[:NEW_REL]->(:ENDNODE(s)))"
                                          ^

Answer 1

Cypher语言不允许节点模式包含返回节点的函数（即使这样做非常方便）。

此查询（首先创建节点变量s和e，以便可以在节点模式中使用该查询）应该为您工作：

MATCH
  (p1:Category {catName: "Main_topic_classifications"}), 
  (p2:Category {catName: "Monarchs_of_the_Bulgars"}),
  path = allShortestPaths((p2)-[:SUBCAT_OF*]->(p1))
UNWIND RELATIONSHIPS(path) AS rel
WITH STARTNODE(rel) AS s, ENDNODE(rel) AS e
MERGE (s)-[:NEW_SUBCAT]->(e)

从路径创建新关系（neo4j）

1 个答案: