试图避免嵌套的for循环,但是我不确定如何在一个衬里使用words = x.split()
和words[y:y+n]
。
n = 1
for x in data:
words = x.split()
for y in range(len(words)-n+1):
print(words[y:y+n])
到目前为止,我正在处理以下内容:
data = ' '.join([(x, y) for x in data words = x.split() for y in range(len(words)-n+1) words[y:y+n]])
答案 0 :(得分:1)
分配临时变量的一种解决方法是改为遍历1个元组:
data = ' '.join(words[y:y+n] for x in data for words in (x.split(),) for y in range(len(words)-n+1))
答案 1 :(得分:0)
n = 1
for x in data:
words = x.split()
for y in range(len(words)-n+1):
print(words[y:y+n])
n永远不会改变,所以总是1
for x in data:
words = x.split()
for y in range(len(words)-1+1):
print(words[y:y+1])
因此简化
for x in data:
words = x.split()
for y in range(len(words)):
print(words[y])
基本上是
for x in data:
for word in x.split():
print(word)
这使我们进入
data=' '.join(word for x in data for word in x.split())