Question

我有下一个JSON

{
  "updated": [
    {
      "id": "1",
      "email": "api.test@test.io",
      "businessUnit": "US",
      "firstName": "John",
      "lastName": "Doe",
      "age": 21,
      "gender": "male"
    },
    {
      "id": "2",
      "email": "api.test@test.io",
      "businessUnit": "US",
      "firstName": "John",
      "lastName": "Doe",
      "age": 22,
      "gender": "male"
    },
    {
      "id": "3",
      "email": "api.test@test.io",
      "businessUnit": "US",
      "firstName": "John",
      "lastName": "Doe",
      "age": 23,
      "gender": "male"
    }
  ],
  "deleted": [
    {
      "id": "4",
      "email": "api.test@test.io",
      "businessUnit": "US",
      "firstName": "John",
      "lastName": "Doe",
      "age": 31,
      "gender": "male"
    },
    {
      "id": "5",
      "email": "api.test@test.io",
      "businessUnit": "US",
      "firstName": "John",
      "lastName": "Doe",
      "age": 32,
      "gender": "male"
    },
    {
      "id": "6",
      "email": "api.test@test.io",
      "businessUnit": "US",
      "firstName": "John",
      "lastName": "Doe",
      "age": 33,
      "gender": "male"
    }
  ]
}

是否可以通过其他方式而不是更改'id'字段：
- 设置req.updated [0] .id = userId
- 设置req.updated [1] .id = userId
- 设置req.updated [2] .id = userId
是否可以像这样在“更新”和“删除”部分中更改所有“ id”文件：
- 设置req [*]。id = userId

Answer 1

已编辑：好的，所以您想使用批量编辑，并且具有一些逻辑，可以同时增加id-s。因此，请使用以下转换：https://github.com/intuit/karate#json-transforms

请注意，karate.map(x, i)带有一个可选的第二个参数，该参数为您提供循环索引。

* def data = [{}, {}, {}]
* def fun = function(x, i){ x.id = ~~(i + 1); return x }
* def payload = karate.map(data, fun)
* match payload == [{id: 1}, {id: 2}, {id: 3}]

如何在Karate框架中动态更改Big JSON？

1 个答案: