Question

我正在尝试从地址中分离门牌号码和街道名称。

我能够拆分大多数地址，直到我获得一个包含数字和字母作为HouseNumber一部分的地址。

我已经在下面尝试过了，它在大多数情况下都有效。但这对 876A Mountain Breeze Rd 这样的地址不起作用。我无法从其余地址中分割房屋号 876A 。

他们是否可以将 876A 拆分为[门牌号]？

SELECT
   C.CustomerID
   ,CASE
       WHEN ISNUMERIC(LEFT(LTRIM(C.ServiceAddress), CHARINDEX(' ', 
LTRIM(C.ServiceAddress)))) = 1 THEN
           LEFT(LTRIM(C.ServiceAddress), CHARINDEX(' ', 
LTRIM(C.ServiceAddress)))
       ELSE
           NULL
   END AS [House Number]

 ,CASE
       WHEN ISNUMERIC(LEFT(LTRIM(C.ServiceAddress), CHARINDEX(' ', LTRIM(C.ServiceAddress)))) = 1 THEN
           LTRIM(RTRIM(SUBSTRING(
                                    LTRIM(C.ServiceAddress),
                                    CHARINDEX(' ', LTRIM(C.ServiceAddress)) + 1,
                                    LEN(LTRIM(C.ServiceAddress)))))
       ELSE
           LTRIM(RTRIM(C.ServiceAddress))
   END AS [Street Name]
 FROM dbo.Customers AS C

Answer 1

您可以尝试一下，看看是否能给您正确的结果吗？

SELECT
C.CustomerID
,CASE
   WHEN ISNUMERIC(LEFT(LTRIM(C.ServiceAddress), CHARINDEX(' ', 
LTRIM(C.ServiceAddress)))) = 1 OR ISNUMERIC(LEFT(LTRIM(C.ServiceAddress), CHARINDEX(' 
', 
LTRIM(C.ServiceAddress)))) = 0 THEN
       LEFT(LTRIM(C.ServiceAddress), CHARINDEX(' ', 
LTRIM(C.ServiceAddress)))
   ELSE
       NULL
END AS [House Number]

,CASE
   WHEN ISNUMERIC(LEFT(LTRIM(C.ServiceAddress), CHARINDEX(' ', 
LTRIM(C.ServiceAddress)))) = 1 OR ISNUMERIC(LEFT(LTRIM(C.ServiceAddress), CHARINDEX(' 
', LTRIM(C.ServiceAddress)))) = 0 THEN
       LTRIM(RTRIM(SUBSTRING(
                                LTRIM(C.ServiceAddress),
                                CHARINDEX(' ', LTRIM(C.ServiceAddress)) + 1,
                                LEN(LTRIM(C.ServiceAddress)))))
   ELSE
       LTRIM(RTRIM(C.ServiceAddress))
 END AS [Street Name]
FROM dbo.Customers AS C

如何使用SQL分割地址字符串，门牌号码和街道名称？

1 个答案: