Question

我有一个猜谜游戏，我想验证用户输入是否为数字，并且该数字必须在我的范围内（如果在此处甚至是正确的术语），如果不是，则返回一条错误消息，允许用户执行以下操作：再试一次。

我已经设置了猜谜游戏，但是现在我正试图对其设置限制。我尝试使用isdigit（str），但是我不确定我是否完全理解它的工作原理，所以现在有点想让它与TRY和Except一起工作：我还认为我弄乱了之前可以正常工作的代码，因为例如现在输入5时，它表示数字不在1到10之间，所以else语句是错误的。

import random

`enter code here`#Welcome Message
print("Welcome to my Guess the number program!")
print()

guess = ()
number = random.randint(1, 10)
count = 0

#User input/game rules
while True:
    guess = int(input("Guess a number between 1 and 10: "))
    try:
        guess = int(guess)
        if guess<1 or guess>10:
            count += 1
            guess = int(guess)
            print()
            if guess < number:
                print("Too low.")
                print()
            elif guess > number:
                print("Too high.")
                print()
            else:
                print("You guessed it!")
                print("You guessed it in" ,count, "attempts.")
        else:
            print("number not between 1 and 10")
    except:
        print("Invalid input")[enter image description here][1]

这是我开始弄混之前的代码。

import random

#Welcome Message
print("Welcome to my Guess the number program!")
print()

guess = ()
number = random.randint(1, 10)
count = 0

#User input/game rules
while guess != number:
    guess = int(input("Guess a number between 1 and 10: "))
    count += 1
    print()
    if guess < number:
        print("Too low.")
        print()
    elif guess > number:
        print("Too high.")
        print()
    elif guess == number:
        print("You guessed it!")
        print("You guessed it in" ,count, "attempts.")
    else:
        break

Answer 1

这是错误的

// Do not forget the Rule import at the top of your controller
use Illuminate\Validation\Rule;

// Then in your method
$this->validate(request(), [
    'name' => 'required',
    'username' => [
        'required',
        Rule::unique('users', 'username')->ignore($user)
    ]
]);

当猜测为if guess<1 or guess>10:时，则为5，然后进入

False

您需要

else:
   print("number not between 1 and 10")

或更短

if guess>=1 and guess=<10:

您在三个地方使用if 1 <= guess =< 10:

int()

，但是您只能执行一次。

您应该在guess = int(input("Guess a number between 1 and 10: ")) try: guess = int(guess) if guess<1 or guess>10: count += 1 guess = int(guess)

内部进行操作

try/except

Answer 2

对您的代码的评论：

将您的“输入语句”放入try ... except中。
仅一次使用int（）
如果逻辑不正确
计数变量应为1而不为零
重复空的print（）如果将其打印出额外的新行，则可以在上一个打印语句中添加'\ n'

请参阅以下有关其工作原理的mods：

import random
#Welcome Message
print("Welcome to my Guess the number program!\n")
number = random.randint(1, 10)
count = 1

while True:
    try:
        guess = int(input("Guess a number between 1 and 10: "))
        if guess>=1 and guess<=10:
            count += 1
            if guess < number:
                print("Too low.")
            elif guess > number:
                print("Too high.")
            else:
                print("You guessed it!")
                print("You guessed it in" ,count, "attempts.")
        else:
            print("number not between 1 and 10")
    except:
        print("Invalid input")

在我的猜测游戏中验证用户输入为整数

2 个答案: