Question

我正在尝试查询样本，以便仅在名称不包含“ CP”的情况下才显示结果。因此，如果名称为“ CP”，则不显示该样本的行，但是，如果名称为“ Dirt”或“ Dust”，则不显示该样本号的行。 / p>

这是我的尝试：

select distinct SampNum
from results
where (SampName = 'Dirt' or SampName = 'Dust')
  and SampName not in ('CP')

原始数据：

SampNum | SampName
1         'Dirt'
1         'Dust'
1         'CP'
2         'Dirt'
2         'Dust'
3         'Dust'
4         'CP'

预期输出：

SampNum                     
2               
3

Answer 1

试一下...

select distinct SampNum 
from results 
where (SampName = 'Dirt' or SampName = 'Dust') 
and SampNum not in (Select SampNum From results Where SampName in ('CP'))

Answer 2

您可以在此处使用EXCEPT来返回带有污垢或灰尘的SampNum-那些也具有CP的除外：

select SampNum
from results
where (SampName = 'Dirt' or SampName = 'Dust')
EXCEPT
select SampNum
from results
where SampName = 'CP'

dbfiddle https://dbfiddle.uk/?rdbms=sqlserver_2017&fiddle=0bd2b69767319581d91fd5c484de2583

create table results (SampNum int, SampName varchar(10));
insert into results values (1,'Dirt');
insert into results values (1,'Dust');
insert into results values (1,'CP');
insert into results values (2,'Dirt');
insert into results values (2,'Dust');
insert into results values (3,'Dust');
insert into results values (4,'CP');

select SampNum
from results
where (SampName = 'Dirt' or SampName = 'Dust')
EXCEPT
select SampNum
from results
where SampName = 'CP';

返回：

SampNum
      2
      3

Answer 3

您可以进行聚合：

select SampNum
from results
group by SampNum
having sum(case when SampName in ('Dirt', 'Dust') then 1 else 0 end) > 0 and
       sum(case when SampName = 'CP' then 1 else 0 end) = 0;

仅列出不包含名称的样本

3 个答案: