Question

我需要在特定时间段（datediff 18小时或22小时）内汇总行中的值（Amount2），还需要知道使用了多少行。这些值的总和必须在ID号内完成。有人可以帮忙吗？

表T1的第一行：

"scripts": {
...
    "reactotron": "adb reverse tcp:9090 tcp:9090 && /opt/Reactotron/reactotron-app",
...
}

我需要的是一个脚本，该脚本将从PickupDate时间在18小时或22小时之内的行中求和Amount2，还计算求和的行（必须在ID中完成）。

ID  PickupDateTime          Amount2 DifferenceToPrevious
1   2019-04-02 04:44:19.000 6458    0d 00:13:17:000
1   2019-04-02 04:31:02.000 5385    0d 02:34:50:000
1   2019-04-02 01:56:12.000 1545    0d 18:06:18:000
1   2019-04-01 07:49:54.000 3466    1d 02:23:51:000
1   2019-03-31 05:26:03.000 7505    0d 00:13:53:000
1   2019-03-31 05:12:10.000 5080    0d 03:28:18:000
1   2019-03-31 01:43:52.000 1166    0d 18:02:49:000
1   2019-03-30 07:41:03.000 2991    1d 02:39:49:000
1   2019-03-29 05:01:14.000 7065    0d 00:13:11:000
2   2019-04-01 04:56:21.000 9518    1d 23:52:21:000
2   2019-03-30 05:04:00.000 9638    2d 00:34:29:000
2   2019-03-28 04:29:31.000 9499    1d 23:28:47:000
2   2019-03-26 05:00:44.000 10117   2d 00:03:41:000
2   2019-03-24 04:57:03.000 9933    1d 23:50:06:000
2   2019-03-22 05:06:57.000 9869    2d 00:25:01:000

Answer 1

测试数据：

(?<=>)https:\/\/test.be\/assets\/kcfinder\/upload\/files\/[\w\.]*

查询以获取所需的结果。关键是使用带有适当declare @tbl table (ID int, PickupDateTime datetime2(3), Amount2 int) insert into @tbl values (1, '2019-04-02 04:44:19.000', 6458), (1, '2019-04-02 04:31:02.000', 5385), (1, '2019-04-02 01:56:12.000', 1545), (1, '2019-04-01 07:49:54.000', 3466), (1, '2019-03-31 05:26:03.000', 7505), (1, '2019-03-31 05:12:10.000', 5080), (1, '2019-03-31 01:43:52.000', 1166), (1, '2019-03-30 07:41:03.000', 2991), (1, '2019-03-29 05:01:14.000', 7065), (2, '2019-04-01 04:56:21.000', 9518), (2, '2019-03-30 05:04:00.000', 9638), (2, '2019-03-28 04:29:31.000', 9499), (2, '2019-03-26 05:00:44.000', 10117), (2, '2019-03-24 04:57:03.000', 9933), (2, '2019-03-22 05:06:57.000', 9869);子句的子查询：

where

Answer 2

@MichałTurczyn的查询将提供正确的数据，同时还需要进行5次扫描（1个主扫描+ 4个子查询）。您只需再进行一次扫描即可更有效地完成此操作：

declare @tbl table (ID int,  PickupDateTime datetime2(3), Amount2 int)
insert into @tbl values
(1,   '2019-04-02 04:44:19.000', 6458),
(1,   '2019-04-02 04:31:02.000', 5385),
(1,   '2019-04-02 01:56:12.000', 1545),
(1,   '2019-04-01 07:49:54.000', 3466),
(1,   '2019-03-31 05:26:03.000', 7505),
(1,   '2019-03-31 05:12:10.000', 5080),
(1,   '2019-03-31 01:43:52.000', 1166),
(1,   '2019-03-30 07:41:03.000', 2991),
(1,   '2019-03-29 05:01:14.000', 7065),
(2,   '2019-04-01 04:56:21.000', 9518),
(2,   '2019-03-30 05:04:00.000', 9638),
(2,   '2019-03-28 04:29:31.000', 9499),
(2,   '2019-03-26 05:00:44.000', 10117),
(2,   '2019-03-24 04:57:03.000', 9933),
(2,   '2019-03-22 05:06:57.000', 9869);

SELECT pickup.*, subCalc.*
  FROM @tbl pickup
 CROSS 
 APPLY (SELECT SUM(incl.include18) AS count18
             , SUM(incl.include18 * sub.Amount2) AS amount18
             , SUM(incl.include22) AS count22
             , SUM(incl.include22 * sub.Amount2) AS amount22
          FROM @tbl sub
         CROSS
         APPLY (SELECT IIF(DATEADD(HOUR, -18, pickup.pickupdatetime) <= sub.PickupDateTime, 1, 0) AS include18
                     , IIF(DATEADD(HOUR, -22, pickup.pickupdatetime) <= sub.PickupDateTime, 1, 0) AS include22
             ) incl
         WHERE pickup.PickupDateTime >= sub.PickupDateTime
           AND pickup.id = sub.id
     ) subCalc
ORDER BY pickup.PickupDateTime DESC

Working example on dbfiddle。

Answer 3

Select sum(Amount2) as sum_amount_2, Count(*) as n_lines_summed
From table
WHERE PickupDateTime between DateDiff(HOUR, -22, GetDate()) and DateDiff(HOUR, -18, GetDate())
Group by Id

类似的东西？我认为很简单。

Answer 4

您需要类似的东西吗？

select * from 
(    Select PickupDateTime  sum(Amount2) as sum_amount_18, Count(*) as n_lines_summed18
    From table
    WHERE PickupDateTime <=  DateDiff(HOUR, -18, GetDate())
    Group by PickupDateTime  )X join 
(    Select PickupDateTime  sum(Amount2) as sum_amount_22, Count(*) as n_lines_summed22
    From table
    WHERE PickupDateTime <=  DateDiff(HOUR, -22, GetDate())
    Group by PickupDateTime  )y on X.PickupDateTime  =  Y.PickupDateTime

SQL查询以汇总特定时间段内（ID内）行中的值？

4 个答案: