Question

假设我有四个现有数组：

var one =   ["apple","banana","berry"];
var two =   ["fobar", "barfoo", "farboo"];
var three = [13, 421];
var four =  ["seven", "eight", "eleven"];

如何将它们合并为一个数组并以最简单的方式返回？我得到的是

var result = [1、2、3、4];

导致

|-----------------------------|
|  apple  |  banana  | berry  |  
|  foobar |  barfoo  | farboo |  
|  13     |  421     |        |
|  seven  |  eight   | eleven |
|-----------------------------|

但是，我真正需要的是这个

|------------------------------------|
|  apple  |  foobar  | 13  |  seven  |
|  banana |  barfoo  | 421 |  eight  |
|  berry  |  farboo  |     |  eleven |
|------------------------------------|

Answer 1

JavaScript没有多维数组，它具有数组数组。

如果您还没有one，two，three，four数组，则可以使用单个嵌套文字来实现：

var result = [
    ["apple", "fobar", 13, "seven"],
    ["banana", "barfoo", 421, "eight"],
    ["berry", undefined, "eleven"]
];

实时示例：

var result = [
    ["apple", "fobar", 13, "seven"],
    ["banana", "barfoo", 421, "eight"],
    ["berry", "farboo", undefined, "eleven"]
];
console.log(result);

.as-console-wrapper {
  max-height: 100% !important;
}

如果您已经拥有它们，因为它们是列值的数组，并且显然您希望子数组是行值，所以需要循环：

var result = [];
for (var i = 0; i < 3; ++i) {
    result[i] = [
        one[i], two[i], three[i], four[i]
    ];
}

实时示例：

var one =   ["apple","banana","berry"];
var two =   ["fobar", "barfoo", "farboo"];
var three = [13, 421];
var four =  ["seven", "eight", "eleven"];
var result = [];
for (var i = 0; i < 3; ++i) {
    result[i] = [
        one[i], two[i], three[i], four[i]
    ];
}
console.log(result);

.as-console-wrapper {
  max-height: 100% !important;
}

Answer 2

尝试

var output = one.map(function(e,i){
  return [e].concat([two, three, four].map(function(f){
    return f[i] === undefined ? '': f[i];
  }))
})
console.info(output);

Google表格：返回多维数组（JavaScript）

2 个答案: