复杂的IF语句

时间:2019-04-12 19:16:32

标签: python-3.x

我正在尝试编写一个程序,该程序根据以下规则为每个GROUP选择一个Customer_Address_ID。

如果Group_ID中的地址代码计数> = 2并且Group_ID中的CUST#计数= 1然后选择带有CUST#的地址代码

如果Group_ID中的地址代码计数> = 2并且Group_ID中的CUST#计数> = 2然后考虑该组中的Cust#

如果只有1个CUST#以G /#开头,则选择与该CUST#关联的Customer_Address_ID

如果有2个以上以C /#开头的Cust#,请选择Customer_Address_ID

如果没有以G /#开头的CUST#,请检查是否有以字母/字母开头的。如果只有一个以字母/字母开头,请选择与该CUST#相关联的Customer_Address_ID

如果2个以上字母/字母开头,请选择与任何一个相关联的Customer_Address_ID

如果没有以G /#或字母开头的CUST#,请检查是否有以A /#开头的

如果2+以A /#开头,请选择与较低CUST#相关联的Customer_Address_ID。

到目前为止,我具有每个组ID的Address_Code和Group_ID计数。...非常感谢您的帮助。

  

将熊猫作为pd导入      导入xlrd      将numpy导入为np

     

将Excel读入数据框

     

df = pd.read_excel(“ C:...........主要地址ID分配示例。xlsx”)

     

将特定列中的Null替换为任意值,例如0

     

df ['CUST#'] = df ['CUST#']。fillna(0)

     

查找每个唯一组ID的所有列的非零和

     

df2 = df [['GROUP_ID','CUSTOMER_ADDRESS_ID','CUST#']]。groupby('GROUP_ID')。agg(np.count_nonzero)

     

重命名列

     

df2.columns = ['CUSTOMER_ADDRESS_ID_COUNT','CUST#_COUNT']

     

联接两个数据框的列-使用df3的索引联接

     

df3 = df.join(df2,on = ['GROUP_ID'],how ='left')

+====================+==========+=====================+===========+
| PRIMARY_ADDRESS_ID | GROUP_ID | CUSTOMER_ADDRESS_ID |   CUST#   |
+====================+==========+=====================+===========+
|                    | 15       | 672390              |           |
+--------------------+----------+---------------------+-----------+
|                    | 15       | 12491               | BRSSSS    |
+--------------------+----------+---------------------+-----------+
|                    | 8        | 712154              | G99999    |
+--------------------+----------+---------------------+-----------+
|                    | 8        | 273672              | G2KKKK    |
+--------------------+----------+---------------------+-----------+
|                    | 7        | 649202              | GDLLL     |
+--------------------+----------+---------------------+-----------+
|                    | 7        | 714617              | ERHHHH    |
+--------------------+----------+---------------------+-----------+
|                    | 7        | 398899              |           |
+--------------------+----------+---------------------+-----------+
|                    | 9        | 672390              | A67860    |
+--------------------+----------+---------------------+-----------+
|                    | 9        | 12491               | A67861    |
+--------------------+----------+---------------------+-----------+
| EXPECTED OUTPUT    |          |                     |           |
+--------------------+----------+---------------------+-----------+
| PRIMARY_ADDRESS_ID | GROUP_ID | CUSTOMER_ADDRESS_ID | CUSTOMER# |
+--------------------+----------+---------------------+-----------+
| 12491              | 15       | 672390              |           |
+--------------------+----------+---------------------+-----------+
| 12491              | 15       | 12491               | BRSSSS    |
+--------------------+----------+---------------------+-----------+
| 712154             | 8        | 712154              | G99999    |
+--------------------+----------+---------------------+-----------+
| 712154             | 8        | 273672              | G2KKKK    |
+--------------------+----------+---------------------+-----------+
| 649202             | 7        | 649202              | G2DLLL    |
+--------------------+----------+---------------------+-----------+
| 649202             | 7        | 714617              | ERHHHH    |
+--------------------+----------+---------------------+-----------+
| 649202             | 7        | 398899              |           |
+--------------------+----------+---------------------+-----------+
| 672390             | 9        | 672390              | A67860    |
+--------------------+----------+---------------------+-----------+
| 672390             | 9        | 12491               | A67861    |
+--------------------+----------+---------------------+-----------+

0 个答案:

没有答案
相关问题