在Tkinter中按下给定按钮时,我无法触发随机函数

时间:2019-04-13 20:55:06

标签: python tkinter

我正在制作一个按钮,它将在Python的tkinter模块中显示一条消息。

首先,按钮上有文字。单击后,将显示一个消息框。消息框是“弹出窗口”或“错误消息”。

下面的代码将显示执行上述语句的示例函数。

def joke1():
    messagebox.showinfo(title = "There are three types of people in this world", message = "Those who can count and those who can't.")

root = Tk()
root.title("Joke Board 1.0 by Jamlandia")
root.iconbitmap(r"C:\Users\VMWZh\Downloads\Icons8-Ios7-Messaging-Lol.ico")
button = Button(text = "There are three types of people in this world", bg = '#42f474', fg = 'black', command = joke1)
test = Button()

button.grid(column = 0, row = 0)

test.grid(column = 1, row = 0)
root.mainloop()

我想不出一种方法来对其进行编码,因此当您按下按钮时,它将运行与按钮上显示的笑话相关的功能,然后将其随机绑定到一个新功能上,并将文本绑定到更改为与此功能相关的笑话。

1 个答案:

答案 0 :(得分:0)

  

问题:按下按钮,...随机...开玩笑

tkinter — Tcl / Tk的Python接口

Python教程和Python模块


点击Joke即可显示随机 Button,而无需messagbox

import tkinter as tk
import random

class App(tk.Tk):
    def __init__(self):
        super().__init__()

        self.joke_index = 0
        self.jokes = [("There are three types of people in this world", "Those who can count and those who can't."),
                      ('Grew up with six brothers', 'That’s how I learned to dance–waiting for the bathroom'),
                      ('Always borrow money from a pessimist.', 'He won’t expect it back.')
                      ]

        self.label1 = tk.Label(self)
        self.label1.grid(row=0, column=0, pady=3)

        self.label2 = tk.Label(self)
        self.label2.grid(row=1, column=0, pady=3)

        button = tk.Button(self,
                           text='Show next Joke',
                           command=self.show_random_joke,
                           bg='#42f474', fg='black'
                           )
        button.grid(row=2, column=0, pady=3)

    def show_random_joke(self):
        v = -1
        while v == self.joke_index:
            v = random.randrange(0, len(self.jokes)-1)
        self.joke_index = v

        self.label1['text'], self.label2['text'] = self.jokes[self.joke_index]

if __name__ == "__main__":
    App().mainloop()

使用Python测试:3.5