Question

为什么foreach循环仅打印数组中的第一个值？

$Jdata_cate = '[{"category_id":"103","name":"Martin","parent_id":0},{"category_id":"10","name":"Juan","parent_id":0},{"category_id":"9","name":"Kasi","parent_id":0}]';
    $J_Min = strtolower($Jdata_cate);
    $J_MinDecoded = json_decode($J_Min, true);

    $Ddata_cate = '[{"category_id":"55","name":"Abc","parent_id":0},{"category_id":"41","name":"Pedro","parent_id":0},{"category_id":"40","name":"Kasi","parent_id":0}]';
    $D_Min = strtolower($Ddata_cate);
    $D_MinDecoded = json_decode($D_Min, true);

    $both_arrays = array_merge((array)$J_MinDecoded, (array)$D_MinDecoded);

    $Delete_repeated = array_unique($both_arrays);

    foreach($Delete_repeated as $y=>$y_value){
            echo $y_value['name'] . '<br>';
    }

Answer 1

问题是您调用array_unique($both_arrays)的默认行为是将项目作为字符串进行比较，但是它们是数组，因此失败。

解决方案是添加SORT_REGULAR标志作为第二个参数。

$Delete_repeated = array_unique($both_arrays, SORT_REGULAR);

Answer 2

尝试此解决方案：

function array_unique_multidimensional($array, $key)
{
    $temp_array = array();
    $i = 0;
    $key_array = array();

    foreach ($array as $val) {
        if (!in_array($val[$key], $key_array)) {
            $key_array[$i] = $val[$key];
            $temp_array[$i] = $val;
        }
        $i++;
    }
    return $temp_array;
}

$Jdata_cate = '[{"category_id":"103","name":"Martin","parent_id":0},{"category_id":"10","name":"Juan","parent_id":0},{"category_id":"9","name":"Kasi","parent_id":0}]';
$J_Min = strtolower($Jdata_cate);
$J_MinDecoded = json_decode($J_Min, true);

$Ddata_cate = '[{"category_id":"55","name":"Abc","parent_id":0},{"category_id":"41","name":"Pedro","parent_id":0},{"category_id":"40","name":"Kasi","parent_id":0}]';
$D_Min = strtolower($Ddata_cate);
$D_MinDecoded = json_decode($D_Min, true);

$both_arrays = array_merge((array)$J_MinDecoded, (array)$D_MinDecoded);

$Delete_repeated = array_unique_multidimensional($both_arrays, 'name');

foreach ($Delete_repeated as $y => $y_value) {
    echo $y_value['name'] . '<br>';
}

此处使用的是我定义的函数，而不是array_unique

foreach循环仅在循环中输出第一个值

2 个答案: