如何使用mysqli prepare语句获取最后一条记录的insert_id,例如以下内容?
$stmt = $this->mysqli->prepare("INSERT INTO test (name) values (?)")
$stmt->bind_param('s', $name);
$stmt->execute();
答案 0 :(得分:8)
$new_id = $this->mysqli->insert_id;
(在$stmt->execute()
之后)
答案 1 :(得分:2)