Question

我正在尝试使用多个键值字典创建一个参数请求，并且它创建的很好。但是每次使用随机键-值顺序创建字典时。如何对字典键进行排序或排序。示例：

    [
      "mbappdetails": [
"locationdtls": [
          "ipAdress": "100.105.100.6",
          "locationDtl": "NaviMumbai,Maharashtra",
          "longdtl": "73.0152077",
          "latdtl": "19.1112212"
        ],
        "appdtls": [
          "appregflg": "00",
          "appid": "com.mmcompany.nstapp",
          "applversion": "1.0.70",
          "pushnkey": "cVCzsSyxCLr4l5JPElHWLDiNuoQJcbFmRlN5LFWZM9hN5lYYZnJy_4Kvvu2_fAjBXhGxbKpt"
        ],
        "devicedtls": [
          "deviceserial": "ExtEYNBSO8D85KR7DCEIOSHH",
          "devicemodel": "iPod Touch 6",
          "os": "iOS",
          "simflag": "N",
          "devicesdkversion": "12.10",
          "deviceproduct": "iPod Touch 6",
          "deviceid": "XXXXX-A2F5-XXXX-8EAC-XXXXX",
          "devicemake": "iPod touch",
          "rootflg": "N",
          "devicebrand": "APPLE",
          "osVersion": "12.1.4"
        ],
        "channelid": "XXXXXXRRRRRR"
      ],
      "token": "myToken",
      "signcs": "encrypted_dictionary_key_values_with_signature_key"
    ]

订单应为：channelid，appdtls，devicedtls，locationdtls，令牌，signcs

输出必须仅在字典中。

Answer 1

不幸的是，Dictionary数据结构不是为任何排序的存储设计的。但是，您可以对键进行排序并以数组的形式获取它。

let dictionary = [
    "A" : [1],
    "Z" : [3],
    "C" : [2]
]

let keysSorted = Array(dictionary.keys).sorted(<)

然后，您可以遍历已排序的数组并通过键查找字典值。希望对您有帮助！

Answer 2

您没有添加任何代码，因此可以尝试以下操作：（您可以根据需要更改符号。要以哪种升序或降序排列）

let sortedDict = YourDictionary.sorted(by: {$0.0 > $1.0})

如果您要调用API，则参数的顺序无关紧要。

Answer 3

您尝试以下代码。

    var dict = ["name" : "Test", "user" : "Users" ]
    dict = [String : String](uniqueKeysWithValues: dict.sorted{ $0.key < $1.key 
    })

按关键字排序字典

3 个答案: