为回调分配上下文

Question

我有一个带有接口的Asynctask类，该类在完成后会回调到另一个类。问题是，一旦我调用了asynctask，它将根据onpostexecute上设置的代码每5s重新执行一次，而不管当前活动是什么。问题是我需要访问当前活动的接口，而不是启动Asynctask的接口。

我正在尝试创建一个变量Context contexto并将其更新为当前活动的上下文（每个活动的onCreate方法都具有MainActivity.contexto = this;。我想将onpostexecute上的回调更改为当前活动活动，而不是起源于所有活动的活动，这样我就可以从该活动的界面访问输出。

这是到目前为止我的MainActivity内容：

public class MainActivity extends AppCompatActivity implements ClimateAPI.OnDownloadComplete, DownloadArduino.OnArduinoDownloadComplete,LuzPopup.ExampleDialogListener {

    public static Context contexto;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        getSupportActionBar().hide();
        setContentView(R.layout.activity_main);
        DownloadArduino downloadArduino = new DownloadArduino(MainActivity.this);
        downloadArduino.executeOnExecutor(AsyncTask.THREAD_POOL_EXECUTOR);
    }

    @Override
    public void onArduinoDownloadComplete(String temp, String humi, String lum, String light) {
        Log.d(TAG, "onArduinoDownloadComplete: entrou ");
        TextView textTempArd = (TextView) findViewById(R.id.textTempArd);
        textTempArd.setText(temp+"°C" );
        TextView textUmidArd = (TextView) findViewById(R.id.textUmidArd);
        textUmidArd.setText(humi+ "%");
        TextView textLumArd = (TextView) findViewById(R.id.textLumArd);
        textLumArd.setText(lum);

        if((DownloadArduino.lightstate==1) && (DownloadArduino.luminosity<300) && (contexto==this)) {
            LuzPopup luzPopup = new LuzPopup();
            luzPopup.show(getSupportFragmentManager(), "example dialog");
        }    
    }

这就是我的AsyncTask中的内容：

public class DownloadArduino extends AsyncTask<String,Void,Void> {

    private static final String TAG = "DownloadArduino";
    public int internetAccess = 0; /*Variavel que checa acessibilidade da internet ( 0 = inacessivel, 1 = acessivel )*/
    public static String umidade;
    public static String temperatura;
    public static String luminosidade;
    public static int lightstate;
    public static int luminosity;
    public static String light;
    public String result;
    private final OnArduinoDownloadComplete mCallBack;

    interface OnArduinoDownloadComplete{
            void onArduinoDownloadComplete(String temp, String humi, String lum, String light);
        }

    public DownloadArduino(OnArduinoDownloadComplete callBack) {
        Log.d(TAG, "DownloadArduino: callback e" + callBack);
        mCallBack = callBack;
    }

    @Override
    protected void onPostExecute(Void aVoid) {
        Log.d(TAG, "onPostExecute: contexto e " + MainActivity.contexto);
        if (internetAccess == 0 ){ /*Output para o caso de nao haver conexao desde o comeco do metodo*/
            Toast.makeText(MainActivity.contexto, "Verifique a conexão", Toast.LENGTH_LONG).show(); /*Nao ha conexao*/
        }
        mCallBack.onArduinoDownloadComplete(temperatura,umidade,luminosidade,light);
        if (MainActivity.logado) {
            Handler handler = new Handler();
            handler.postDelayed(new Runnable() {

                @Override
                public void run() {
                    DownloadArduino downloadArduino = new DownloadArduino((OnArduinoDownloadComplete) MainActivity.contexto);
                downloadArduino.executeOnExecutor(AsyncTask.THREAD_POOL_EXECUTOR);
                }
        }, 5000);
    }
}

问题是我无法将上下文应用于回调，是否有办法做到这一点，以便被回调的活动始终是当前活动（而不是调用asynctask的活动）？