Ts类严格初始化

Question

提出这个问题是因为我不完全理解打字稿“ strictPropertyInitialization”及其带来的影响。 不确定是否在我的SmartObject类中立即初始化功能Activate（），dispose（）和deactivate（），有人可以帮助并解释正确的方法吗？

// Disposable Mixin
class Disposable {
    isDisposed:boolean
    constructor() { 
        this.dispose = this.dispose
    }
    dispose() {
        this.isDisposed = true;
    }

}

// Activatable Mixin
class Activatable {
    constructor(public isActive:boolean) { }
    activate() {
        this.isActive = true;
    }
    deactivate() {
        this.isActive = false;
    }
}

class SmartObject implements Disposable, Activatable {

    // Disposable
    isDisposed: boolean = false;
    dispose: () => void;
    // Activatable
    isActive: boolean = false;
    activate: () => void;
    deactivate: () => void;

    constructor() {
        setInterval(() => console.log(this.isActive + " : " + this.isDisposed), 500);
        this.dispose = this.dispose;
        this.activate = this.activate;
        this.deactivate = this.deactivate;
    }

    interact() {
        this.activate();
        this.dispose()
    }

}
applyMixins(SmartObject, [Disposable, Activatable]);

let smartObj = new SmartObject();
setTimeout(() => smartObj.interact(), 1000);
const test = new Disposable();
setTimeout(() => { console.log(test.isDisposed) },2000)

////////////////////////////////////////
// In your runtime library somewhere
////////////////////////////////////////

function applyMixins(derivedCtor: any, baseCtors: any[]) {
    baseCtors.forEach(baseCtor => {
        Object.getOwnPropertyNames(baseCtor.prototype).forEach(name => {
            Object.defineProperty(derivedCtor.prototype, name, Object.getOwnPropertyDescriptor(baseCtor.prototype, name));
        });
    });
}

有关打字稿中OOP的任何提示和技巧？