基于一个类的视图中的两种发布方法

时间:2019-04-24 10:29:27

标签: python django api

在一个基于类的视图中是否可以有2个post方法?

我试图做这样的事情,但是当然不起作用

我的自定义视图:

class UserExamDetail(APIView):

    def get_queryset(self, pk):
        return Exam.objects.get(pk=pk)

    def get(self, request, pk):
        exam = self.get_queryset(pk=pk)
        if exam:
            exam_closed = 0
            exam_opened = 0
            c_questions = ClosedQuestion.objects.filter(exam=exam)
            o_questions = OpenedQuestion.objects.filter(exam=exam)
            for question in c_questions:
                points = int(question.points)
                exam_closed += points
            for question in o_questions:
                points = int(question.points)
                exam_opened += points
            exam.score = exam_closed + exam_opened
            exam.save()
        serializer = ExamCreatorSerializer(exam)
        return Response(serializer.data)

    def post(self, request, pk):
        serializer = ClosedQuestionSerializer(data=request.data)
        if serializer.is_valid():
            serializer.save(exam=pk)
            return Response(serializer.data, status=status.HTTP_201_CREATED)
        return Response(serializer.data, status=status.HTTP_400_BAD_REQUEST)

    def post(self, request, pk):
        serializer = OpenedQuestionSerializer(data=request.data)
        if serializer.is_valid():
            serializer.save(exam=pk)
            return Response(serializer.data, status=status.HTTP_201_CREATED)
        return Response(serializer.data, status=status.HTTP_400_BAD_REQUEST)

只有第一个post有效,并且例如当我尝试更改函数名称:post1和post 2时,Django不会将此方法识别为post。如果有可能这样做,那么我也很好奇我是否应该执行这种视图,或者Post方法应该是单独的视图?

1 个答案:

答案 0 :(得分:3)

您可以将其他数据传递到请求正文,并确定要使用的序列化程序。这是一个例子。

def post(self, request, pk):
    if request.POST.get('is_opened'):
        serializer_class = OpenedQuestionSerializer
    else:
        serializer_class = ClosedQuestionSerializer

    serializer = serializer_class(data=request.data)
    if serializer.is_valid():
        serializer.save(exam=pk)
        return Response(serializer.data, status=status.HTTP_201_CREATED)
    return Response(serializer.data, status=status.HTTP_400_BAD_REQUEST)