是否有Cadence工作流程基于外部输入更改睡眠时间的示例?
我正在寻找的场景是这样的:工作流程进入睡眠状态,直到时间X,但是在睡眠开始之后但尚未完成之前,有一个外部触发器导致时间X更改为时间Y。Y可以是可以早于X。它甚至可以早于“现在”,这应该立即释放睡眠。
答案 0 :(得分:0)
这是您要查找的代码段
func SampleTimerWorkflow(ctx workflow.Context, timerDelay time.Duration) error
{
logger := workflow.GetLogger(ctx)
resetCh := workflow.GetSignalChannel(ctx, "reset")
timerFired := false
delay := timerDelay
for ;!timerFired; {
selector := workflow.NewSelector(ctx)
logger.Sugar().Infof("Setting up a timer to fire after: %v", delay)
timerCancelCtx, cancelTimerHandler := workflow.WithCancel(ctx)
timerFuture := workflow.NewTimer(timerCancelCtx, delay)
selector.AddFuture(timerFuture, func(f workflow.Future) {
logger.Info("Timer Fired.")
timerFired = true
})
selector.AddReceive(resetCh, func(c workflow.Channel, more bool) {
logger.Info("Reset signal received.")
logger.Info("Cancel outstanding timer.")
cancelTimerHandler()
var t int
c.Receive(ctx, &t)
logger.Sugar().Infof("Reset delay: %v seconds", t)
delay = time.Second * time.Duration(t)
})
logger.Info("Waiting for timer to fire.")
selector.Select(ctx)
}
workflow.GetLogger(ctx).Info("Workflow completed.")
return nil
}
现在您可以发送信号将计时器重置为10秒,如下所示:
cadence-cli --domain <domain> wf signal -w <workflow_id> --name reset --input 10