基于多个条件的数组查找或过滤

时间:2019-04-25 14:25:34

标签: angular typescript

我有具有不同数据的数据列表,如下所示

[0: {lat: "37.829998", lng: "-122.003152", title: "Allocate", pairStatus: 1, …}
1: {lat: "37.829998", lng: "-122.003152", title: "Commission", pairStatus: 1, …}
2: {lat: "37.829998", lng: "-122.003152", title: "Aggregate", pairStatus: 1, …}
3: {lat: "37.7745586", lng: "-121.9610328", title: "Ship", pairStatus: 1, …}
4: {lat: "37.7745586", lng: "-121.9610328", title: "Ship", pairStatus: 1, …}
5: {lat: "37.7745586", lng: "-121.9610328", title: "Ship", pairStatus: 1, …}
6: {lat: "37.7745586", lng: "-121.9610328", title: "Receive", pairStatus: 1, …}
7: {lat: "37.7745586", lng: "-121.9610328", title: "Receive", pairStatus: 1, …}]

我需要如下输出-将lat和lan分组为标题

[0: {lat: "37.829998", lng: "-122.003152", title: "Allocate,Commission,Aggregate"}
1: {lat: "37.7745586", lng: "-121.9610328", title: "Ship,Ship,Ship,Receive,Receive"}]

1 个答案:

答案 0 :(得分:0)

您可以使用Array reduce()来实现。如果累加器中已经存在具有相同纬度和经度的项目,则在累加器中查找元素,然后将标题连接到现有项目中。

如果项目不存在,则将具有“ lat”,“ lng”和“ title”属性的新项目推入累加器

let rawData = [  {lat: "37.829998", lng: "-122.003152", title: "Allocate", pairStatus: 1},
{lat: "37.829998", lng: "-122.003152", title: "Commission", pairStatus: 1},
{lat: "37.829998", lng: "-122.003152", title: "Aggregate", pairStatus: 1},
{lat: "37.7745586", lng: "-121.9610328", title: "Ship", pairStatus: 1},
{lat: "37.7745586", lng: "-121.9610328", title: "Ship", pairStatus: 1},
{lat: "37.7745586", lng: "-121.9610328", title: "Ship", pairStatus: 1},
{lat: "37.7745586", lng: "-121.9610328", title: "Receive", pairStatus: 1},
{lat: "37.7745586", lng: "-121.9610328", title: "Receive", pairStatus: 1}]

let finalData = rawData.reduce((acc, {lat, lng, title}) => {
  let found = acc.find((e) => {
    return lat === e.lat && lng === e.lng
  })
  
  if (found) {
     found.title = `${found.title},${title}`
  }
  else {
    acc.push({lat, lng, title})
  }
  return acc
}, [])

console.log(finalData)

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