Question

我有一家处理赔偿金的公司的数据库。我必须。我正在处理三个表：结论，m_email和m_lead。在“结论”表中，除其他外，我有：id和创建日期。在m_email表中，我有：id，打开了多少，单击了多少。在m_lead表中：id，结论ID，creation_date。我需要检查以下内容： 1.将年份分为四个部分，检查一月至四月，四月至七月等的申请数量。 2.接下来，我需要附加一个表格以获取类似信息。例如：

ID = 1      
number_of_aplications = 5000     
number_of_leads = 7000

下面，我放置了代码。我有两个问题： 1.我不知道如何增加三个月才能得出一个结果。 2.我不知道如何将引线数量连接到此代码

select date_part('month', creating_date) as "1-3", count(id) as 
"Number of applications"
from applications
where date_part('month', creating_date) between  '01' and '03' AND
date_part('year', creating_date) between '2017' and '2018'
group by  date_part('month', creating_date)
order by count(id) DESC ;

Answer 1

您的需求对我来说有点难以理解。但是对于您问题的第一部分，我想我可以回答：

初始情况

您有一个表'applications（id int主键，creation_date时间戳）'

您需要什么（据我了解）

每三个月（一月至三月，以此类推）有申请数量

可能的解决方案

select a.delta, sum(applicationByMonth) as applicationByMonth, sum(leadByMonth) as leadByMonth
from 
(
    select '1 trimester' as delta, cast(date_part('month', creation_date) as int) as month, count(id) as applicationByMonth
    from applications
    where cast(date_part('month', creation_date) as int) <= 3
    group by cast(date_part('month', creation_date) as int)
    union
    select '2 trimester' as delta, cast(date_part('month', creation_date) as int) as month, count(id) as applicationByMonth
    from applications
    where cast(date_part('month', creation_date) as int) between 4 and 6
    group by cast(date_part('month', creation_date) as int)
    union
    select '3 trimester' as delta, cast(date_part('month', creation_date) as int) as month, count(id) as applicationByMonth
    from applications
    where cast(date_part('month', creation_date) as int) between 7 and 9
    group by cast(date_part('month', creation_date) as int)
    union
    select '4 trimester' as delta, cast(date_part('month', creation_date) as int) as month, count(id) as applicationByMonth
    from applications
    where cast(date_part('month', creation_date) as int) between 10 and 12
    group by cast(date_part('month', creation_date) as int)
) as a
inner join 
(
    select '1 trimester' as delta, cast(date_part('month', creation_date) as int) as month, count(id) as leadByMonth
    from m_lead
    where cast(date_part('month', creation_date) as int) <= 3
    group by cast(date_part('month', creation_date) as int)
    union
    select '2 trimester' as delta, cast(date_part('month', creation_date) as int) as month, count(id) as leadByMonth
    from m_lead
    where cast(date_part('month', creation_date) as int) between 4 and 6
    group by cast(date_part('month', creation_date) as int)
    union
    select '3 trimester' as delta, cast(date_part('month', creation_date) as int) as month, count(id) as leadByMonth
    from m_lead
    where cast(date_part('month', creation_date) as int) between 7 and 9
    group by cast(date_part('month', creation_date) as int)
    union
    select '4 trimester' as delta, cast(date_part('month', creation_date) as int) as month, count(id) as leadByMonth
    from m_lead
    where cast(date_part('month', creation_date) as int) between 10 and 12
    group by cast(date_part('month', creation_date) as int)
) as l 
    on a.delta = l.delta
group by a.delta
order by 1;

我认为您可以从那里开始适应自己的需求。

希望这会有所帮助;）

结合两个表和求和Postgresql

1 个答案: