猫鼬,如何清空收藏集

时间:2019-04-26 07:53:36

标签: node.js mongodb mongoose

我有以下hapi.js服务器

const Hapi = require('hapi')
const Mongoose = require('mongoose')
const Wreck = require('wreck');


const server = new Hapi.Server({
    "host": "localhost",
    "port": 3000
})

Mongoose.connect('mongodb://localhost/myDB', { useNewUrlParser: true })

const BlockModel = Mongoose.model('block', {
    height: Number,
    size: Number,
    time: Number
})

server.route({
    method: "GET",
    path: "/",
    handler: async (request, h) => {

        Mongoose.model.blocks.remove({});    //<------This is the part of the code I intend to use to delete the collection

        const { res, payload } = await Wreck.get('https://api.url');
        let myJson = JSON.parse(payload.toString()).blocks
        console.log(myJson)
        for (let i = 0; i<myJson.length; i++) {
            var block = new BlockModel({  height: myJson[i].height, size: myJson[i].size, time: myJson[i].time });
            block.save();
        }
        console.log(myJson)

        return "test"
    }
})



server.start();

要点是,它可以正常工作并将所需的数据保存到我的集合中,但是如果我不删除每次执行的数据,则数据库将保持增长。所以我打算实现类似于

db.blocks.remove({}) //where blocks is my collection

哪个在mongoconsole中可以正常工作。 但是我找不到如何在代码中实现

2 个答案:

答案 0 :(得分:1)

您可以将deleteMany运算符与空过滤器一起使用。

db.collection.deleteMany({})

或您的模型:

await BlockModel.deleteMany({})

答案 1 :(得分:-1)

清空数据库中的所有集合

const collections = await mongoose.connection.db.collections();

for (let collection of collections) {
    await collection.deleteMany({})
}