我收到错误表或视图不存在

时间:2019-04-29 03:53:17

标签: php sql database oracle

我已经在oracle中实现了表,但无法使用此php访问所有表:

  const ContentPane = function() {}
  const Films = function () {}

  ContentPane.prototype.getTemplate = async function(){
    const filmsTemplate = await new Films().render();
    let template = `
        <div class="contentPane" id="contentPane">
        ${filmsTemplate}
        </div>
    `;
    return template;
  }


  Films.prototype.render =  function(){
    var template =  this.getTemplate();
    return template.then(function(val){
      return val;
    })
    //based on the value resolved by promise,
    //appropriate template should be returned to parent
  }

  Films.prototype.getTemplate = async function(){
    //make network call
    //create template based on server response
    return await new Promise((resolve) => {
      resolve('123')
    })
  }

  new ContentPane().getTemplate().then(template => {
    console.log(template);
  });

如果我执行相同的代码,但是我选择了Doctors表,则它可以工作,但在其他任何表上却不能。 请帮助。

0 个答案:

没有答案
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