从Java pojo生成xml,而无需使用注释

时间:2019-05-01 18:56:40

标签: java xml jackson jaxb jackson-dataformat-xml

我需要将Java pojo封送为xml,并且pojo是API的一部分,因此我无法进行任何更改,例如添加任何jaxb注释,是否还有其他方法可以将这些Java objecta转换为xml(例如任何API,例如Jackson等。)而无需使用注释。

1 个答案:

答案 0 :(得分:0)

您可以使用Stax解析器。

Device级(例如):

public class Device {

    private String name;
    private String model;

    public Device(String name, String model) {
        this.name = name;
        this.model = model;
    }

    //Getters & Setters
}

使用XMLStreamWriter Object 解析为 xml

List<Device> deviceList = ...

StringWriter stringWriter= new StringWriter();
XMLStreamWriter xmlWriter = XMLOutputFactory
            .newFactory()
            .createXMLStreamWriter(stringWriter);

xmlWriter.writeStartDocument();
xmlWriter.writeCharacters("\n");
xmlWriter.writeStartElement("devices");     // write <devices>
xmlWriter.writeCharacters("\n");

for(Device d : deviceList){
    xmlWriter.writeCharacters("\t");
    xmlWriter.writeStartElement("device");  // write <device>
    xmlWriter.writeCharacters("\n\t\t");
    xmlWriter.writeStartElement("name");    // write <name>
    xmlWriter.writeCharacters(d.getName()); // write <name> value
    xmlWriter.writeEndElement();            // write </name>
    xmlWriter.writeCharacters("\n\t\t");
    xmlWriter.writeStartElement("model");   // write <model>
    xmlWriter.writeCharacters(d.getModel());// write <model> value
    xmlWriter.writeEndElement();            // write </name>
    xmlWriter.writeCharacters("\n\t");
    xmlWriter.writeEndElement();            // write </device>
    xmlWriter.writeCharacters("\n");
 }
 xmlWriter.writeEndElement();               // write </devices>
 xmlWriter.writeEndDocument();
 xmlWriter.close();

 System.out.println(stringWriter.toString());         // print result

结果:

<?xml version="1.0" ?>
<devices>
  <device>
    <name>iPhone</name>
    <model>6s</model>
  </device>
  <device>
    <name>iPhone</name>
    <model>7</model>
  </device>
  <device>
    <name>iPad</name>
    <model>2</model>
  </device>
</devices>