Question

这似乎不会更新记录。谁能明白为什么？

    try {
        $status = 'OK';
        $messId = 179981;
        #die(var_dump($messId, $this->campaignId, $this->userId, $status));
        $stmt = $this->dbh->prepare("UPDATE tbl_inbound_responses SET status = :status, sent = '1' WHERE fk_userId = :userId AND fk_campaignId = :campId AND pk_messageId = :messId") or die("Prepare Error");
        $stmt->bindParam(':userId', $this->userId);
        $stmt->bindParam(':campId', $this->campaignId);
        $stmt->bindParam(':messId', $messId);
        $stmt->bindParam(':status', $status);
        $stmt->execute();

        #var_dump($stmt->debugDumpParams(), $stmt->errorInfo());

        if($err = $stmt->errorInfo()) {
            if($err[0] != '00000') {
                var_dump($stmt->debugDumpParams());
            }
        }               

    }
    catch(PDOException $e) {
        die($e->getMessage());
    }

该脚本也有

$this->dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);

设置和

$stmt->debugDumpParams();

报告：

SQL: [120] UPDATE tbl_inbound_responses SET status = :status, sent = '1' WHERE fk_userId = :userId AND fk_campaignId = :campId AND pk_messageId = :messId
Params: 4
Key: Name: [7] :userId paramno=-1 name=[7] ":userId" is_param=1 param_type=2
Key: Name: [7] :campId paramno=-1 name=[7] ":campId" is_param=1 param_type=2
Key: Name: [7] :messId paramno=-1 name=[7] ":messId" is_param=1 param_type=2
Key: Name: [7] :status paramno=-1 name=[7] ":status" is_param=1 param_type=2
NULL array(3) { [0]=> string(5) "00000" [1]=> NULL [2]=> NULL }

干杯。

编辑：

我不相信它是：

PHP PDO Update prepared statement problem或PHP PDO Prepared statement query not updating record

Answer 1

如果您没有收到异常，那么SQL查询或PDO如何破坏它没有任何问题。最可能的原因是参数问题。所以尝试调试它。只用以下内容替换->bindParam来电：

    $params = array(
         ':userId' => $this->userId,
         ':campId' => $this->campaignId,
         ':messId' => $messId,
         ':status' => $status,
    );
    var_dump($params);
    $stmt->execute($params);

这可能会提示。如果失败，请尝试?枚举参数。在任何情况下，使用SQL中的原始“字符串值”重新运行相同的查询以进行测试（在您选择的任何查询工具中）。

Answer 2

您的查询中存在

问题！使用“，”而不是“AND”：

$stmt = $this->dbh->prepare("UPDATE tbl_inbound_responses SET status = :status, sent = 1 WHERE fk_userId = :userId, fk_campaignId = :campId, pk_messageId = :messId") or die("Prepare Error");

pdo准备好的声明没有更新

2 个答案: