Question

我有一个csv文件，其中包含名称和均值列表。例如：

ali,5.0
hamid,6.066666666666666
mandana,7.5
soheila,7.833333333333333
sara,9.75
sina,11.285714285714286
sarvin,11.375

我将用三个较低的平均值重写csv。我已经编写了代码，但是再次写入csv时遇到了问题。我应该保持均值作为输入。

import csv
import itertools
from collections import OrderedDict
with open ('grades4.csv', 'r') as input_file:
    reader=csv.reader(input_file)
    val1=[]
    key=list()
    threelowval=[]
    for row in reader:
        k = row[0] 
        val=[num for num in row[1:]] #seperate a number in every row 
        key.append(k) #making a name -key- list
        val1.append(val) #making a value list
        value = list(itertools.chain.from_iterable(val1)) #making a simple list from list of list in value
        value=[float(i) for i in value] ##changing string to float in values
    #print(key)
    #print(value)
    dictionary = dict(zip(key, value))
    #print(dictionary)
    findic=OrderedDict(sorted(dictionary.items(), key=lambda t: t[1])) ##making a sorted list by OrderedDict
    #print(findic)
##make a separation for the final dict to derive the three lower mean
    lv=[]
    for item in findic.values():
            lv.append(item)
    #print(lv)
    for item in lv[0:3]:
            threelowval.append(item)
    print(threelowval)

我尝试了下面的代码，但出现错误。

with open('grades4.csv', 'w', newline='') as output_file_name:
    writer = csv.writer(output_file_name)
    writer.writerows(threelowval)

预期结果：

5.0
6.066666666666666
7.5

Answer 1

您应该尝试以下操作：

with open('grades4.csv', 'w', newline='') as output_file_name:
   writer = csv.writer(output_file_name)
   for i in threelowval:
       writer.writerow([i])

Answer 2

我尝试使用下面的代码并收到正确的结果。

with open('grades4.csv', 'w', newline='') as output_file_name:
    writer = csv.writer(output_file_name)
    writer.writerows(map(lambda x: [x], threelowval))

将代码的输出写入CSV文件

2 个答案: