python

时间:2019-05-07 03:56:24

标签: python interpolation bilinear-interpolation

我的线性插值有一些逻辑错误,它在某些情况下有效,但不能完全起作用。

我尝试使用不同的方式来编写外推情况的逻辑。

def interpolate(x, y, x_test):
    for i in range(len(x)):
        if x[i] > x_test:   #extrapolated condition: when the largest value of
            x_below = i - 1 #list x is greater than x_test 
            x_above = i 
            y_below = i - 1
            y_above = i
            break
        elif x[i] < x_test: #extrapolated condition: when the largest value of 
            x_below = i + 1 #list x is greater than x_test 
            x_above = i 
            y_below = i + 1
            y_above = i
            break                
        else:             #interpolated condition: when x_test lies between  
            return y[i]    #two sample points.

    #a = (yabove - ybelow) / (xabove - xbelow)         
    a = (y[y_above] - y[y_below]) / (x[x_above] - x[x_below])  
    #b = ybelow - a * xbelow
    b = y[y_below] - a * x[x_below]
    #y’ = a * x’ + b
    return a * x_test + b  

interpolate([1, 3, 5], [1, 9, 25], 5.0) 我希望输出为25,但实际输出为17.0。

1 个答案:

答案 0 :(得分:0)

我认为您正在寻找这样的东西:

def interpolate(x, y, x_test):
    for i in range(len(x)):
        if x[i] > x_test:   #extrapolated condition: when the largest value of
            x_below = i - 1 #list x is greater than x_test
            x_above = i
            y_below = i - 1
            y_above = i
            continue # <---- I changed break to continue
        elif x[i] < x_test: #extrapolated condition: when the largest value of
            x_below = i + 1 #list x is greater than x_test
            x_above = i
            y_below = i + 1
            y_above = i
            continue # <---- I changed break to continue
        else:             #interpolated condition: when x_test lies between
            return y[i]    #two sample points.

    #a = (yabove - ybelow) / (xabove - xbelow)
    a = (y[y_above] - y[y_below]) / (x[x_above] - x[x_below])
    #b = ybelow - a * xbelow
    b = y[y_below] - a * x[x_below]
    #y’ = a * x’ + b
    return (a * x_test + b)

print(interpolate([1, 3, 5], [1, 9, 25], 5.0))

输出:

25

注意,我将breaks更改为continues

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