Question

使用CommonJS，我可以执行以下操作：

generator.js：

module.exports = (...args) => ({
  create: makeCreate(...args),
  remove: makeRemove(...args),
});

model.js：

const generate = require('generator.js');

module.exports = generate('my-model');

use.js：

const { create, remove } = require('model.js');

module.exports = {
  doCreate: () => create('something'),
  doRemove: () => remove('something else'),
};

使用ES6模块，我可以重构为以下内容：

generator.mjs：

export default (...args) => ({
  create: makeCreate(...args),
  remove: makeRemove(...args),
});

model.mjs：

import generate from 'generator.mjs';

export default generate('my-model');

use.mjs：

import model from 'model.mjs';

export const doCreate = () => model.create('something');
export const doRemove = () => model.remove('something else');

但是，model.mjs本身的导出方式意味着我无法做到这一点：

use.mjs：

import { create, remove } from 'model.mjs';

export const doCreate = () => create('something');
export const doRemove = () => remove('something else');

我想不出一种在generator.mjs和model.mjs中简洁定义导出的方法，以实现上述目的。可以吗？

Answer 1

替代品：

您可以在use.mjs

中执行类似的操作

import model from 'model.mjs';

const {create, remove} = model;

export const doCreate = () => create('something');
export const doRemove = () => remove('something else');

另一个解决方案是：

在model.mjs

import generate from "./generator.js";

export const { create, remove } = generate("my-model");

在use.mjs

中

import { create, remove } from "./model.js";

export const doCreate = () => create("something");
export const doRemove = () => remove("something else");

ES6导出模板生成器

1 个答案: