Question

如何从数据框中提取folder \ filename.txt

我的数据框：

C:\folder\one\file.txt
C:\folder\subfolder\two\file2.txt

我需要输出最后一个文件夹和文件名：

df:
one\file.txt
two\file2.txt

我的代码：

df[0] = df[0].apply(lambda x: x.split('\\')[-1]) # i am receiving only file.txt - only filename , not last folder and filename

Answer 1

稍微修改您的通话：

import os
df[0] = df[0].apply(lambda x: os.sep.join(x.split('\\')[-2:])))

在这里，os.sep是系统分隔符，它使呼叫系统独立。您也可以使用其他任何字符串。

Answer 2

尝试：

# This function takes in input a list and converts it into a dir chain string
def convert(string_list): 

    string = "" 

    # traversing each element of the list and using it to create a new string  
    for x in string_list: 
        string += x + "\\"

    # returning string[:-1] to get rid of the redundant \ in the end of the string (not advised when location is of a directory)
    return string[:-1] 


a = r"C:\folder\one\file.txt"

print(convert(a.split("\\")[-2:]))

输出：

one\file.txt

在python中从数据框中提取文件夹和文件名

2 个答案: