Question

是否有一个选项可以使主线程等待所有工作线程完成？
在下面的代码中，mainThread.js只是创建了worker。
工人要花很长时间执行。
在这种情况下，如何指示主线程等待所有线程执行完毕？
与Java中的thread.join（）类似。

mainThread.js：

const {Worker, parentPort, workerData} = require('worker_threads');
const path = require('path');

const startWorker = function(path, workerData, callback) {
    //Create worker thread
    let worker = new Worker(path, {workerData});

    //Listen to events of the worker thread
    worker.on('message', (msg) => {
        callback(null, msg);
    });
    worker.on('error', callback);
    worker.on('exit', (code) => {
        if(code !== 0) {
            console.error(`Error: Non-zero exit code ${code}`)
        }
    });

    //Return the worker thread
    return worker;
};

console.log('This is Main Thread');

//Create and start worker threads
let thread1 = startWorker(__dirname + path.sep + 'workerThread.js', "user1", (error, result) => {
    if(error) return console.error(error);
    console.log('Result: ', result);
});

let thread2 = startWorker(__dirname + path.sep + 'workerThread.js', "user2", (error, result) => {
    if(error) return console.error(error);
    console.log('Result: ', result);
});

workerThread.js：

const {workerData, parentPort} = require('worker_threads');
setTimeout(() => {
    console.log(workerData);
    parentPort.postMessage(workerData + "done");
}, 2000)

执行：node --experimental-worker mainThread.js

PS：我们可以尝试通过将其作为http服务器实例运行或使setTimeout具有很大的值来使其工作。但是，nodejs本身是否有实现此问题的选项。

[Nodejs-worker-threads]：主线程是否可以选择等待所有工作线程完成？

0 个答案: