Question

递归函数中的计数器-我有一个函数试图在列表中找到最大的数字。当然，j将被设置回0，计数器声明应该在哪里？

  import random



list = []

for i in range(0, 10):
    number = random.randint(0, 100)
    list.append(number)

print(list)


def bigger_number (list):
    j = 0.  #where to place this
    n = list[0]  #where to place this
    while j < 9:
        if n >= list[j]:
            list[j] = n
            j+=1
            bigger_number(list)




print("The biggest number in the list is : ",n)

bigger_number(list)

Answer 1

根据我的理解，您希望使用递归解决方案从数组中获取更大的数量。

如果是，请尝试以下功能：

# ListA = [123,45,89,58]
# lenA = len(ListA) 

def bigger_Number(ListA, lenA): 
    if (lenA == 1): 
        return ListA[0] 
    return max(ListA[lenA - 1], bigger_Number(ListA, lenA - 1))

递归函数中的计数器

1 个答案: