Question

我想从表格中选择一个足球比赛的结果，将主队得分与客队得分进行比较，并进行总计，如下所示：

如果主队得分为>客队得分= Win
如果<客队得分小于Loss
如果等于=客队得分= Draw

我有2列要使用：hometeamscore和awayteamscore。

我知道此代码仅占一列：

SELECT sum(hometeamscore) FROM tablename

我该怎么办才能知道PHP中有多少赢家和输家？

例如：

Game1: Home Team 3 - 0 Away Team
Game2: Home Team 2 - 0 Away Team
Game3: Home Team 1 - 1 Away Team
Game4: Home Team 3 - 2 Away Team

结果：

Win = `2`
Loss = `1`
Draw = `1`

Answer 1

根据您给定的详细信息，您的表格将如下所示。

CREATE TABLE score (
    id INT AUTO_INCREMENT,
    hometeamscore TINYINT,
    awayteamscore TINYINT,
    PRIMARY KEY (id)
)  ENGINE=INNODB;



INSERT score (hometeamscore,awayteamscore) values 
(3,0),(2,0),(1,1),(1,5);

您需要使用3个简单的查询分别获得赢，输和卓的结果，如下所示：

SELECT count(id) as Win FROM score where hometeamscore > awayteamscore;

SELECT count(id) as Loss FROM score where hometeamscore < awayteamscore;

SELECT count(id) as Drow FROM score where hometeamscore = awayteamscore;

Answer 2

无法通过一个查询获得结果，但是我们可以使用mysql的UNION来获取它。您可以得到如下结果：-

SELECT CONCAT('Win:- ', count(id)) as result FROM `scores` WHERE `hometeamscore` > `awayteamscore`
UNION
SELECT CONCAT('Draw:- ',count(id)) as result FROM `scores` WHERE `hometeamscore` = `awayteamscore`
UNION
SELECT CONCAT('Loss:- ',count(id)) as result FROM `scores` WHERE `hometeamscore` < `awayteamscore`

Answer 3

这也将：

SELECT Result,COUNT(*) AS 'Total' FROM
     (SELECT 
            CASE WHEN hometeamscore > awayteamscore THEN 'Win'
            WHEN hometeamscore = awayteamscore THEN 'Draw'
            WHEN hometeamscore < awayteamscore THEN 'Loss' 
                 END AS Result
     FROM score) v 
GROUP BY result;

在这种情况下，我是否使用命令“ sum”？

3 个答案: