使用索引将二进制字符串转换为整数数组

Question

我有4个二进制数据字符串；我想使用每个列将输出作为整数，即

p1 = '10010010101111' 
p2 = '11100011110001' 
p3 = '00001110101101' 
p4 = '00101100010010'

我想将输出作为整数作为 [p1 p2 p3 p4]

以下代码不断返回语法错误。我要去哪里错了？

for i in range(0,len(p1),1):
    x = [p1[i],p2[i],p3[i],p4[i]]
    y = ''.join(map(str,x))
    z[i] = int(y,2)

Answer 1

您可以使用zip（）转置列，并使用本机二进制字符串转换来获取数值：

z = [ int("".join(bits),2) for bits in zip(p1,p2,p3,p4) ]
print(z) # [12, 4, 5, 8, 3, 3, 14, 4, 14, 5, 10, 10, 9, 14]

Answer 2

我在以下方面度过了轻松的时光：

p1 = '10010010101111' 
p2 = '11100011110001' 
p3 = '00001110101101' 
p4 = '00101100010010'

p =[p1,p2,p3,p4]

y=[]
for element in p:
    y.append(bin(int(element,2)))


print(y)

如果只想将二进制的十进制值作为整数，则不要将bin（）放在上面的for循环中。

输出：

Answer 3

另一种选择：

p1 = '10010010101111' 
p2 = '11100011110001' 
p3 = '00001110101101' 
p4 = '00101100010010'

p = [p1,p2,p3,p4]

y = [int(x,2) for x in p]

Answer 4

尝试一下：

p1 = '10010010101111' 
p2 = '11100011110001' 
p3 = '00001110101101' 
p4 = '00101100010010'
p =[p1,p2,p3,p4]
z = list(map(int, p)) # Keeps the strings in binary format
z1 = [int(i,2) for i in p] # Converts strings to decimal formatted integer

输出：

[10010010101111, 11100011110001, 1110101101, 101100010010]
[9391, 14577, 941, 2834]