Question

目标是与Google表格一起发送表格数据，以将其记录在适当的字段中。我使用了article，但是我的脚本给出了一个错误：

{
"result": "error",
  "Error in: ": {
  "message": "Invalid argument: id",
  "name": "Exception",
  "fileName": "Code",
  "lineNumber": 20,
  ""smack": "\that Code:20 (handleResponse)\n\tat Code:2 (doGet)\n"
  }
}

请帮助我找出我在Google Apps脚本中发生的错误，或者告诉我如何自己诊断错误。

Google Apps脚本：

function doGet(e){
  return handleResponse(e);
}

//  Enter sheet name where data is to be written below
        var SHEET_NAME = "Table";

var SCRIPT_PROP = PropertiesService.getScriptProperties(); // new property service

function handleResponse(e) {
  // shortly after my original solution Google announced the LockService[1]
  // this prevents concurrent access overwritting data
  // [1] http://googleappsdeveloper.blogspot.co.uk/2011/10/concurrency-and-google-apps-script.html
  // we want a public lock, one that locks for all invocations
  var lock = LockService.getPublicLock();
  lock.waitLock(30000);  // wait 30 seconds before conceding defeat.

  try {
    // next set where we write the data - you could write to multiple/alternate destinations
    var doc = SpreadsheetApp.openById(SCRIPT_PROP.getProperty("key"));
    var sheet = doc.getSheetByName(SHEET_NAME);

    // we'll assume header is in row 1 but you can override with header_row in GET/POST data
    var headRow = e.parameter.header_row || 1;
    var headers = sheet.getRange(1, 1, 1, sheet.getLastColumn()).getValues()[0];
    var nextRow = sheet.getLastRow()+1; // get next row
    var row = []; 
    // loop through the header columns
    for (i in headers){
      if (headers[i] == "Timestamp"){ // special case if you include a 'Timestamp' column
        row.push(new Date());
      } else { // else use header name to get data
        row.push(e.parameter[headers[i]]);
      }
    }
    // more efficient to set values as [][] array than individually
    sheet.getRange(nextRow, 1, 1, row.length).setValues([row]);
    // return json success results
    return ContentService
          .createTextOutput(JSON.stringify({"result":"success", "row": nextRow}))
          .setMimeType(ContentService.MimeType.JSON);
  } catch(e){
    // if error return this
    return ContentService
          .createTextOutput(JSON.stringify({"result":"error", "error": e}))
          .setMimeType(ContentService.MimeType.JSON);
  } finally { //release lock
    lock.releaseLock();
  }
}

function setup() {
    var doc = SpreadsheetApp.getActiveSpreadsheet();
    SCRIPT_PROP.setProperty("key", doc.getId());
}

Answer 1

您收到此错误，是因为您忘记执行Google Apps脚本的添加。

要执行此操作-转到“运行”菜单，然后选择“设置”。

将表单数据提交到Google表格时，Google App脚本中出现错误

1 个答案: