Question

我正在编写SharePoint应用程序。那里有下拉列表页面。我有 SelectedIndexChanged的处理程序。我想获取选定的值，但为CustomObject，我看到的唯一选项是string。我尝试过SelectedValue，现在仍然是string。

这就是我设置列表的方式：

protected void Page_Load(object sender, EventArgs e)
{
    List<CustomObject> customList = //retrieving data
    myDropDownList.DataSource = customList.Select(x => new { x.Name, Value = x});
    myDropDownList.DataTextField = "Name";
    myDropDownList.DataValueField = "Value";
    myDropDownList.DataBind();
}

那是我尝试的方法之一：

protected void myDropDownList_SelectedIndexChanged(object sender, EventArgs e)
{
    var index = groupingDropDownList.SelectedIndex;
    CustomObject obj =  (CustomObject)myDropDownList.Items[index].Value;
    obj.DoSomething();
}

有可能吗？还是我必须在某处有对象的字典？

Answer 1

您将需要利用html5数据属性，然后可以将其放在下拉选项中。这是您可以如何处理数据的示例。

          // add Agencies' addresses as HTML5 data-attributes.
            var agencies = agencyNames.ToList();
            for (int i = 0; i < requesting_agency.Items.Count - 1; i++) {
                requesting_agency.Items[i + 1].Attributes.Add("data-address", 
                agencies[i].address);
                servicing_agency.Items[i + 1].Attributes.Add("data-address", 
                agencies[i].address);
            }

然后，在处理信息时，您可以执行类似的操作。

    var index = groupingDropDownList.SelectedIndex;
    var selectedText = myDropDownList.Items[index].SelectedValue;
    var selectedValue = myDropDownList.Items[index].Attributes["attribute"];
    // put into obj
    // do something with object

如果您有任何疑问，请告诉我。

Answer 2

您要将对象(x => new { x.Name, Value = x})绑定到下拉值，应将实际值绑定到该对象。

测试演示：

public class CustomObject
    {
        public int ID { get; set; }
        public string Name { get; set; }

        public CustomObject(int _ID,string _Name)
        {
            this.ID = _ID;
            this.Name = _Name;
        }
    }
    public partial class WebForm1 : System.Web.UI.Page
    {
        protected void Page_Load(object sender, EventArgs e)
        {
            List<CustomObject> customList = new List<CustomObject>();
            customList.Add(new CustomObject(1,"test1"));
            customList.Add(new CustomObject(2,"test2"));
            myDropDownList.DataSource = customList.Select(x => new { x.Name, Value = x.ID });
            myDropDownList.DataTextField = "Name";
            myDropDownList.DataValueField = "Value";
            myDropDownList.DataBind();
        }
    }

从自定义类类型的ASP SharePoint DropDownList获取选定的值

2 个答案: