如何将多个值传递给参数?

时间:2019-05-22 15:37:31

标签: sql-server tsql

我正在尝试在我的select语句中传递一个或多个输入变量

我尝试使用IN语句

DECLARE @LOANKIND VARCHAR(100)
SET @LOANKIND = 'Payables - Loan,Payables - Lines of Credit'
SELECT * from Table
WHERE LOANKIND.KIND_DESC IN (@LOANKIND)

我所有可能的值是:

应付账款-贷款,应付账款-信贷额度,应付账款-可收回赠款,应付账款-赠款,应付账款-债券,应付账款-担保,应收款-贷款,应收款-信贷额度,应收款-可收回赠款,应收款-担保

2 个答案:

答案 0 :(得分:1)

您可以为此使用动态查询。如下所示:

DECLARE @sql nvarchar(max)
DECLARE @LOANKIND VARCHAR(100)
SET @LOANKIND = '''Payables - Loan'', ''Payables - Lines of Credit'''
SET @sql = 'SELECT * from Table WHERE LOANKIND.KIND_DESC IN (' + @LOANKIND + ')'

SP_EXECEUTESQL @sql

答案 1 :(得分:0)

另一种方式。

如果您使用的是SQL 2016+,则可以使用STRING_SPLIT。否则,您可以下载DelimitedSplit8K

-- Sample Data
DECLARE @Table TABLE (KIND_DESC VARCHAR(100));
INSERT  @Table(KIND_DESC) VALUES ('Payables - Pizza'),('Payables - Loan'),('Payables - Lines of Credit');

-- Solution
DECLARE @LOANKIND VARCHAR(100) = 'Payables - Loan,Payables - Lines of Credit'

SELECT * 
FROM @Table AS LOANKIND
JOIN STRING_SPLIT(@LOANKIND,',') AS s
ON   LOANKIND.KIND_DESC = s.[value];