继续通过.nextInt获取NoSuchElementException

Question

我的main方法中有一个while(choice == someVal){}块，外面有一个int menu()方法，每次选择后都会提示用户。第一次向用户展示菜单时，它会正确读取输入内容，但是第二次始终存在NoSuchElementException。

主要方法：

public static void main(String[] args) throws SQLException {

    String user = "root";
    String pass = "root123";

    int choice = menu();
    while(choice == 1 || choice == 2) {

        SeenListManager slm = new SeenListManager();

        java.sql.Connection conn = slm.CreateDbConnection(user, pass);
        System.out.println();       

        if(choice == 1) {
            slm.ListAllMedia(conn, 1);
        }
        else if(choice == 2) {

            Scanner in = new Scanner(System.in);

            //get film title
            System.out.print("Enter film title:");
            String title = in.nextLine();

            //rating
            System.out.print("Enter rating (0 to 10):");
            Double rating = in.nextDouble();
            in.nextLine();

            //comments
            System.out.print("Enter any comments: ");
            String review = in.nextLine();
            in.close();

            System.out.println();

            MediaRecord sr = new MediaRecord();

            sr.setTitle(title);
            sr.setRating(rating);
            sr.setComments(review);

            //hard coded user id. 
            slm.AddMediaRecord(conn, 1, sr);
            System.out.println();
        }
        conn.close();
        choice = menu();
    }
} 

然后是menu（）方法：

private static int menu() {

    System.out.println("Choose menu option. Number only.");
    System.out.println();
    System.out.println("1. Print all films");
    System.out.println("2. Add new film to list");
    System.out.println("3. Exit");
    System.out.println();
    System.out.print("Enter choice: ");

    Scanner in = new Scanner(System.in);
    int choice = in.hasNext() ? in.nextInt() : -1;
    in.close();

    return choice;
}

我想念什么？