无法在php中读取/写入文件

时间:2019-05-27 14:36:20

标签: php

我已经阅读了关于stackoverflow可以找到的所有问题!这可能是重复的,但是我无法解决我的问题: 我无法使用php处理文件。

我已使用以下命令获得许可:

sudo chown -R www-data:www-data /var/www/mysite 
sudo chmod -R 777 /var/www/mysite

这是代码:

<?php

if(isset( $_POST['save_values'])) { // retrieve the form data by using the element's name attributes value as key 
    if(!empty($_POST['getURL'])) {
        $URL = $_POST['getURL'];
    }

    if(!empty($_POST['getRefreshRate'])) {
        $RefreshRate = $_POST['getRefreshRate'];
    }

    if(!empty($_POST['getBrightness'])) {
        $Brightness = $_POST['getBrightness'];
    }

}

$filename = "/currentSettings.txt";
chmod($filename,0777);
$cSettings = fopen($filename, "r");

if($cSettings) {
    echo "$cSettings exists";
    while(($line = fgets($cSettings)) !== false) {
         $arr = explode("\n", $line);
         $URL = $arr[0];
         $RefreshRate = $arr[1];
         $Brightness = $arr[2];
    }
    fclose($cSettings);
} else {
    echo "File does not exist";
    fclose($cSettings);
    $cSettings = fopen('/currentSettings.txt', 'w');
    fwrite($cSettings,$URL."\n");
    fwrite($cSettings,$RefreshRate."\n");
    fwrite($cSettings,$Brightness."\n");
    fclose($cSettings);
}

?>

它总是返回File does not exist。它不会写入文件,也不会从文件读取。 我什至在www / mysite内部手动创建了文件,但仍然无法读取。

我对PHP还是很陌生,可以肯定我的代码已损坏,但是找不到解决方法。

这是我解决的方法:

<?php

$filename = "./inputs.txt";
$currentSettingsFile = fopen($filename, "c+");
$array = [];

if($currentSettingsFile) {
    echo "Reading from $filename";
    $array = explode(PHP_EOL, fread($currentSettingsFile, filesize($filename)));
    var_dump($array);
    $URL = $array[0];
    $RefreshRate = $array[1];
    $Brightness = $array[2];
    $closeFlag = fclose($currentSettingsFile);
}

if(isset( $_POST['save_values'])) { // retrieve the form data by using the element's name attributes value as key 

    if(!empty($_POST['getURL'])) {
        $URL = $_POST['getURL'];
        $array[0] = $URL;        
    }

    if(!empty($_POST['getRefreshRate'])) {
        $RefreshRate = $_POST['getRefreshRate'];
        $array[1] = $RefreshRate;
    }

    if(!empty($_POST['getBrightness'])) {
        $Brightness = $_POST['getBrightness'];
        $array[2] = $Brightness;
    }
}

if(!$closeFlag) fclose($currentSettingsFile);

$currentSettingsFile = fopen($filename, "c");
if($currentSettingsFile) {
    echo "Writing in $filename";
    echo fwrite($currentSettingsFile,$array[0].PHP_EOL);
    fwrite($currentSettingsFile,$array[1].PHP_EOL);
    fwrite($currentSettingsFile,$array[2].PHP_EOL);
    fclose($currentSettingsFile);
}

?>

1 个答案:

答案 0 :(得分:1)

$handle似乎没有定义。

这是一个似乎可以在尽可能接近示例的情况下运行的版本,但有一个重要警告:

$filename = "./currentSettings.txt";

if(is_file($filename)) {
    echo "$filename exists";
        $arr = explode("\n", file_get_contents($filename));
        $URL = $arr[0];
        $RefreshRate = $arr[1];
        $Brightness = $arr[2];

} else {
    echo "File does not exist";
    $URL = ''."\n";
    $RefreshRate = ''."\n";
    $Brightness= ''."\n";
    file_put_contents($filename, $URL.$RefreshRate.$Brightness);
    chmod($filename,0777);
}

如果文件不存在,将创建它。 但是 ,由于未定义$URL, $RefreshRate, $Brightness,因此仅向文件添加了三行。

我不确定项目的其余结构,但您可能需要定义一些占位符来填充文件。

相关问题