Question

我已经开发了使用uuid生成条形码和QRCODE的胶子应用程序。使用可以根据商店在条形码和Qrcode之间切换。单击使用时，条形码将仅以纵向屏幕模式显示。因此，当用户单击图像（条形码/ QRcode）时，屏幕将自动旋转。

this.img.setOnMousePressed(event -> {
//Rotate Screen
        Services.get( CMOrientationService.class ).ifPresent( o -> {
            Orientation orientation = Services.get( OrientationService.class )
                    .flatMap(OrientationService::getOrientation)
                    .orElse(Orientation.HORIZONTAL);

            Services.get(LogService.class).ifPresent(service -> service.log("orientation="+orientation.toString()));

            if (orientation == Orientation.VERTICAL) {
                Services.get(LogService.class).ifPresent(service -> service.log("Currently="+orientation.toString()));
                //Change to Barcode
                //GenerateBarQRCode(orientation == Orientation.VERTICAL);
                o.coerceOrientation( Orientation.HORIZONTAL );
            } else {
                Services.get(LogService.class).ifPresent(service -> service.log("Currently="+orientation.toString()));
                //Change to QRCode
                //GenerateBarQRCode(orientation == Orientation.VERTICAL);
                o.coerceOrientation( Orientation.VERTICAL );
            }
            GenerateBarQRCode(orientation == Orientation.VERTICAL);
        } );
});

当用户尝试快速单击图像（双击，三次单击）时，会产生错误。

您可以检查this video了解更多信息（看视频中的6秒）。

已记录。仅在Android中会出错。

Answer 1

您可以像这样使用同步

// At class level
private Object mutex;
//initialize this object in constructor like this
mutex = this;

this.img.setOnMousePressed(event -> {
//Rotate Screen
synchronized(mutex){
// your code here
       ....
}
});

但是，在上述情况下，多个点击事件将以串行方式执行。如果您希望在执行之前忽略多次单击，则可以使用以下代码段

// At class level
private boolean mutex = true;

this.img.setOnMousePressed(event -> {
   if(mutex){
     mutex = false;

        // your code here
               ....
     mutex = true;
   }
});

当MousePressed快速单击或双击，三次单击时，Gluon应用程序出现问题

1 个答案: