Question

如果点列表落在矩形内，我试图获取所有点列表以填充布尔值true。

我试图在Jupyterlab中运行以下代码。但我不断收到以下错误：

TypeError：“ tuple”和“ int”的实例之间不支持“> =”

def allIn(firstCorner=(0,0), secondCorner=(0,0), pointList=[]):
   fc1,sc1=firstCorner[0],firstCorner[1]
   fc2,sc2=secondCorner[0],secondCorner[1]

   fc,sc=pointList[0],pointList[1]
   if (fc >= fc1 and fc <= fc2 and sc >= sc1 and sc <= sc2) :
       return True
   elif(fc >= fc2 and fc <= fc1 and sc >= sc2 and sc <= sc1):
       return True
   else:
       return False

print(allIn((0,0), (5,5), [(1,1), (0,0), (5,5)]))

我希望输出为allIn((0,0), (5,5), [(1,1), (0,0), (5,5)])应该返回True，但是allIn((0,0), (5,5), [(1,1), (0,0), (5,6)])应该返回False 点allIn((0,0), (5,5), [])的空列表应返回False

Answer 1

您的pointsList是一个元组列表。您已设置

fc,sc=pointList[0],pointList[1]

所以fc和sc是元组。

if (fc >= fc1 and fc <= fc2 and sc >= sc1 and sc <= sc2) :

您正在将fc（一个元组）与fc1（一个int）进行比较，这将引发TypeError。为了进行正确的比较，请查看pointList [0] [0]，pointList [0] [1]，pointList [1] [0]等。

Answer 2

查看点列表中的各个点。

def allIn(firstCorner=(0,0), secondCorner=(0,0), pointList=[]):
   fc1,sc1=firstCorner[0],firstCorner[1]
   fc2,sc2=secondCorner[0],secondCorner[1]
   inside = False
   for point in pointList:
       fc,sc=point[0],point[1]
       if (fc >= fc1 and fc <= fc2 and sc >= sc1 and sc <= sc2) :
           inside = True
       elif(fc >= fc2 and fc <= fc1 and sc >= sc2 and sc <= sc1):
           inside = True
       else:
           return False
   return inside

矩形中的点全部

2 个答案: