Question

如果针对所有状态 Q_GRADEBOOK_ID的值为488，而不是返回Q_GRADEBOOK_ID，否则我选择Q_GRADEBOOK_ID，否则返回空

TABLE Q_GB_CAT_SCORE
---------------------------------------------------------
 Q_GRADEBOOK_ID | PERSON_ID | STATUS | Q_GRADEBOOK_CAT_ID
      1         |     1     |  488   |       1
      1         |     1     |  488   |       2
      1         |     2     |  488   |       1
      2         |     2     |  486   |       1
      2         |     2     |  488   |       2

我的查询

 SELECT
 DISTINCT 
 Q_GRADEBOOK_ID 
 FROM 
 Q_GB_CAT_SCORE WHERE
 STATUS IN ('488')

此查询返回此结果

Q_GRADEBOOK_ID
      1        
      2

预期结果

Q_GRADEBOOK_ID
      1

我之所以如此，是因为Q_GRADEBOOK_ID 1返回是因为针对Q_GRADEBOOK_ID 1的所有状态均为488。

Answer 1

您可以排除状态不同的ID：

SELECT distinct 
 Q_GRADEBOOK_ID
  FROM Q_GB_CAT_SCORE
 WHERE Q_GRADEBOOK_ID not in
        (select distinct Q_GRADEBOOK_ID FROM Q_GB_CAT_SCORE WHERE status <> '488')

Answer 2

您可以GROUP BY Q_GRADEBOOK_ID并将条件放在HAVING子句中：

SELECT Q_GRADEBOOK_ID 
FROM Q_GB_CAT_SCORE 
GROUP BY Q_GRADEBOOK_ID
HAVING COUNT(*) = SUM(CASE WHEN STATUS = '488' THEN 1 ELSE 0 END)

或

SELECT Q_GRADEBOOK_ID 
FROM Q_GB_CAT_SCORE 
GROUP BY Q_GRADEBOOK_ID
HAVING SUM(CASE WHEN STATUS <> '488' THEN 1 ELSE 0 END) = 0

仅当所有状态都与返回结果相同时

2 个答案: