出现错误“ Symfony \ Component \ HttpKernel \ Exception \ HttpException”

时间:2019-06-01 04:04:06

标签: ajax laravel

                     $.ajax({

                        method: 'post',
                        url: '{{url("admin/append-course-pricebox-div")}}',
                        data: {_token:{{csrf_token()}},count:boxCount,workshop_id:$("#workshop_id").val()},
                        cache : false,
                        contentType: false,
                        processData: false,
                        success: function (result) {
                            if (result.status == 'success') {
                                $('#success').html('Details are saved successfully.');
                                $('#success_popup .cd-popup').addClass('is-visible');
                            }else if(result.status =='blankTerm'){
                                $("#php-error_includes").show().html(result.message);
                            }
                            $('#preLoader').hide();
                        },
                        error: function (errors) {
                            $('#preLoader').hide();
                            var error = (JSON.parse(errors.responseText));
                            $.each(error.errors, function (key, val) {
                                $('#php-error_'+key).html(val);
                            });
                            $('.php-error').show();
                        }
                    });

当我发布请求时,它显示错误,而Google则由于csrf错误而将其告知我如何将csrf_token传递给控制器​​

1 个答案:

答案 0 :(得分:1)

请遵循以下步骤 1。"_token": "{{ csrf_token() }}",在请求中传递csrf令牌 2。<meta name="csrf-token" content="{{ csrf_token() }}"> 3.详细说明可以在这里enter link description here

相关问题