如何修复此SQL代码中的ORA-00918错误

Question

我的代码出现ORA-00918错误，我找不到问题...以下代码给了我这个错误。

  

ORA-00918：列定义不明确

有人可以给我一些建议吗？谢谢

SELECT * FROM (
 SELECT * FROM (
  SELECT ROWNUM AS RNUM, A.XML_MSG_ID, A.LOGIN_ID, A.ORIGINATOR, A.RECIPIENT, A.ERROR_CODE, B.DOC_NO, B.DOC_NAME, B.ERROR_MSG
  FROM XML_MANAGE_TBL A, XML_REFERENCE_TBL B
  WHERE A.XML_MGS_ID = B.XML_MSG_ID
   AND A.ERROR_CODE <> '00000000'
   AND A.XML_MSG_ID >= '20190528' AND (SUBSTR(A.XML_MSG_ID, 1, 8)) <= '20190604' ) C, EBILL_USER D WHERE D.COMP_NUM = '1258169573' AND C.ORIGINATOR = D.ORIGINATOR )
 WHERE RNUM BETWEEN CASE WHEN (1-1) != 0 THEN ((1-1)*50)+1 ELSE (1-1)*50 END
 AND 1*50;

Answer 1

问题很可能是在第二个子查询select *

中

SELECT * FROM (
  ... subquery C ...
) C, EBILL_USER D WHERE ... AND C.ORIGINATOR = D.ORIGINATOR

表D包含与子查询C相同的列，请确保ORIGINATOR列

只需将第二个查询更改为SELECT C.*，然后仅从D添加所需的列即可。

一般方法如何解决ORA-00918的问题是从最里面的子查询中运行查询，并检查返回的列名是否唯一。

您的情况请先尝试，应该没问题

  SELECT ROWNUM AS RNUM, A.XML_MSG_ID, A.LOGIN_ID, A.ORIGINATOR, A.RECIPIENT, A.ERROR_CODE, B.DOC_NO, B.DOC_NAME, B.ERROR_MSG
  FROM XML_MANAGE_TBL A, XML_REFERENCE_TBL B
  WHERE A.XML_MGS_ID = B.XML_MSG_ID
   AND A.ERROR_CODE <> '00000000'
   AND A.XML_MSG_ID >= '20190528' AND (SUBSTR(A.XML_MSG_ID, 1, 8)) <= '20190604'

比运行第二个最里面的子查询

SELECT * FROM (
  SELECT ROWNUM AS RNUM, A.XML_MSG_ID, A.LOGIN_ID, A.ORIGINATOR, A.RECIPIENT, A.ERROR_CODE, B.DOC_NO, B.DOC_NAME, B.ERROR_MSG
  FROM XML_MANAGE_TBL A, XML_REFERENCE_TBL B
  WHERE A.XML_MGS_ID = B.XML_MSG_ID
   AND A.ERROR_CODE <> '00000000'
   AND A.XML_MSG_ID >= '20190528' AND (SUBSTR(A.XML_MSG_ID, 1, 8)) <= '20190604' ) C, EBILL_USER D WHERE D.COMP_NUM = '1258169573' AND C.ORIGINATOR = D.ORIGINATOR   

在您的IDE（例如SQL Developer）中，您将看到一个或多个带有后缀_1的列，这是重复列的标志，必须排除（对于Equijoin谓词中的列）或重命名。 >

Answer 2

您只需要删除最外面的查询，并在where子句中使用C.RNUM而不是RNUM。尝试以下代码：

SELECT * FROM (
  SELECT ROWNUM AS RNUM, A.XML_MSG_ID, A.LOGIN_ID, A.ORIGINATOR, A.RECIPIENT, A.ERROR_CODE, B.DOC_NO, B.DOC_NAME, B.ERROR_MSG
  FROM XML_MANAGE_TBL A, XML_REFERENCE_TBL B
  WHERE A.XML_MGS_ID = B.XML_MSG_ID
   AND A.ERROR_CODE <> '00000000'
   AND A.XML_MSG_ID >= '20190528' AND (SUBSTR(A.XML_MSG_ID, 1, 8)) <= '20190604' ) C, EBILL_USER D WHERE D.COMP_NUM = '1258169573' AND C.ORIGINATOR = D.ORIGINATOR
  and (C.RNUM BETWEEN CASE WHEN (1-1) != 0 THEN ((1-1)*50)+1 ELSE (1-1)*50 END AND 1*50);