Question

我有两个SQL查询，第一个是：

select Activity, SUM(Amount) as "Total Amount 2009"
from Activities, Incomes
where Activities.UnitName = ? AND
      Incomes.ActivityId = Activities.ActivityID
GROUP BY Activity
ORDER BY Activity;

，第二个是：

select Activity, SUM(Amount) as "Total Amount 2008"
from Activities, Incomes2008
where Activities.UnitName = ? AND
      Incomes2008.ActivityId = Activities.ActivityID
GROUP BY Activity
ORDER BY Activity;

（不要介意'？'，它们代表birt中的参数）。我想要实现的目标如下：我想要一个返回与第一个查询相同的SQL查询，但是有一个额外的（第三）列，看起来与“Total Amount 2008”完全相同（来自第二个查询）。

Answer 1

某些DBMS支持FROM (SELECT ...) AS alias_name语法。

将您的两个原始查询视为临时表。您可以像这样查询它们：

SELECT t1.Activity, t1."Total Amount 2009", t2."Total Amount 2008"
FROM (query1) as t1, (query2) as t2
WHERE t1.Activity = t2.Activity

Answer 2

SELECT Activity, arat.Amount "Total Amount 2008", abull.Amount AS "Total Amount 2009"
FROM
  Activities a
LEFT OUTER JOIN
  (
  SELECT ActivityId, SUM(Amount) AS Amount
  FROM Incomes ibull
  GROUP BY
    ibull.ActivityId
  ) abull
ON abull.ActivityId = a.ActivityID
LEFT OUTER JOIN
  (
  SELECT ActivityId, SUM(Amount) AS Amount
  FROM Incomes2008 irat
  GROUP BY
    irat.ActivityId
  ) arat
ON arat.ActivityId = a.ActivityID
WHERE a.UnitName = ?
ORDER BY Activity

Answer 3

我只想使用Union

在第二个查询中添加额外的列名称，并在其他查询的所有相应位置添加''

实施例

//reverse order to get the column names
select top 10 personId, '' from Telephone//No Column name assigned 
Union 
select top 10 personId, loanId from loan

Answer 4

这对我有用：

select visits, activations, simulations, simulations/activations
   as sims_per_visit, activations/visits*100
   as adoption_rate, simulations/activations*100
   as completion_rate, duration/60
   as minutes, m1 as month, Wk1 as week, Yr1 as year 

from
(
    (select count(*) as visits, year(stamp) as Yr1, week(stamp) as Wk1, month(stamp)
    as m1 from sessions group by week(stamp), year(stamp)) as t3

    join

    (select count(*) as activations, year(stamp) as Yr2, week(stamp) as Wk2,
    month(stamp) as m2 from sessions where activated='1' group by week(stamp),
    year(stamp)) as t4

    join

    (select count(*) as simulations, year(stamp) as Yr3 , week(stamp) as Wk3,
    month(stamp) as m3 from sessions where simulations>'0' group by week(stamp),
    year(stamp)) as t5

    join

    (select avg(duration) as duration, year(stamp) as Yr4 , week(stamp) as Wk4,
    month(stamp) as m4 from sessions where activated='1' group by week(stamp),
    year(stamp)) as t6
)
where Yr1=Yr2 and Wk1=Wk2 and Wk1=Wk3 and Yr1=Yr3 and Yr1=Yr4 and Wk1=Wk4

我使用了连接，而不是联合（我为每个查询需要不同的列，连接将它们全部放在同一列中）然后我删除了引号（与Liam正在做的事情相比），因为它们给了我错误。< / p>

谢谢！没有这个页面，我无法取消它！ PS：对不起，我不知道你是如何用彩色格式化你的陈述的。等

Answer 5

试试这个：

select Activity, SUM(Incomes.Amount) as "Total Amount 2009", SUM(Incomes2008.Amount) 
as "Total Amount 2008" from
Activities, Incomes, Incomes2008
where Activities.UnitName = ?  AND
Incomes.ActivityId = Activities.ActivityID  AND
Incomes2008.ActivityId = Activities.ActivityID GROUP BY
Activity ORDER BY Activity;

基本上你必须使用第一个查询的输出来加入Incomes2008表。

Answer 6

如果您假设两年中所有活动都存在值，那么只需执行内连接，如下所示

 select act.activity, t1.amount as "Total 2009", t2.amount as "Total 2008"
from Activities as act,
    (select activityid,  SUM(Amount) as amount
    from Activities, Incomes
    where Activities.UnitName = ? AND
          Incomes.ActivityId = Activities.ActivityID
    GROUP BY Activityid) as t1,
    (select activityid, SUM(Amount) as amount
    from Activities, Incomes2008
    where Activities.UnitName = ? AND
          Incomes2008.ActivityId = Activities.ActivityID
    GROUP BY Activityid) as t2
    WHERE t1.activityid= t2.activityid
    AND act.activityId = t1.activityId
    ORDER BY act.activity

如果你不能假设这一点，那么看看做外连接

Answer 7

也许不是最优雅的解决方法

select  Activity, 
        SUM(Amount) as "Total_Amount",
        2009 AS INCOME_YEAR
from    Activities, Incomes
where Activities.UnitName = ? AND
      Incomes.ActivityId = Activities.ActivityID
GROUP BY Activity
ORDER BY Activity;

UNION

select  Activity, 
        SUM(Amount) as "Total_Amount",
        2008 AS INCOME_YEAR
from Activities, Incomes2008
where Activities.UnitName = ? AND
      Incomes2008.ActivityId = Activities.ActivityID
GROUP BY Activity
ORDER BY Activity;

Answer 8

您也可以像下面一样使用CTE。

With cte as
(select Activity, SUM(Amount) as "Total Amount 2009"
   from Activities, Incomes
  where Activities.UnitName = ? AND
        Incomes.ActivityId = Activities.ActivityID
  GROUP BY Activity
),
cte1 as 
(select Activity, SUM(Amount) as "Total Amount 2008"
   from Activities, Incomes2008
  where Activities.UnitName = ? AND
        Incomes2008.ActivityId = Activities.ActivityID
  GROUP BY Activity
)
Select cte.Activity, cte.[Total Amount 2009] ,cte1.[Total Amount 2008]      
  from cte join cte1 ON cte.ActivityId = cte1.ActivityID
 WHERE a.UnitName = ?
 ORDER BY cte.Activity

加入两个SQL查询

8 个答案: