我有SOAP代码和URL-在浏览器中输入此URL时，得到以下代码。我的要求是从中获取数据并显示在SSRS中。在底层，它具有ID，名称。如果我通过身份证，我必须得起名字。
https://abcmentsconfig.testing.com/abcments/abcments.asmx?op=GetPeopleFind
POST /abcments/abcments.asmx HTTP/1.1
Host: abcmentsconfig.testing.go.com
Content-Type: text/xml; charset=utf-8
Content-Length: length
SOAPAction: "http://www.testing.go.com/GetPeopleFind"
<?xml version="1.0" encoding="utf-8"?>
<soap:Envelope xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/">
<soap:Header>
<RequestHeader xmlns="http://worldwide.com">
<SourceSystem sourceSystemType="string" sourceSystemDtTm="string" sourceSystemName="string" callChainInitiatedSourceSystemName="string" callChainInitiatedSourceSystemList="string" />
<MessageGenerator generatorName="string" generatorVersion="string" moduleName="string" createDate="string" lastModifiedDate="string" />
<OrgUnitInfo regionNum="string" branchNum="string" satelliteNum="string" orgUnitNum="string" businessSourceNum="string" divCd="string" />
<RequestInfo requestId="string" callChainId="string" contextId="string" sessionId="string" logThisMessageFlag="boolean" eventId="string" transitionId="string" />
<EnableTrace enable="boolean" />
<LoginName networkUserId="string" networkDomainName="string" networkDomainType="string" firstName="string" lastName="string" />
<EnvironmentCd code="string" />
</RequestHeader>
</soap:Header>
<soap:Body>
<PeopleFindInMsg Ver="string" includeAttributes="string" appName="string" xmlns="http://www.testing.org/testingments">
<Application Application="string">
<User UserName="string" NetworkId="string" xmlns="http://www.testing.go.com/UsersPeopleFind" />
<User UserName="string" NetworkId="string" xmlns="http://www.testing.go.com/UsersPeopleFind" />
</Application>
</PeopleFindInMsg>
</soap:Body>
</soap:Envelope>
我已经尝试使用此链接-SOAP call with query on result (SSRS, Sharepoint)
但是，正在获取数据集下的id，div_p，class，p字段，这是不正确的。帮我处理。