Question

我正在创建一个接收用户订单的表，C_ID将存储在C_ID唯一的（StationaryCustomersInfo）表中，并且表（StationaryOrders）将存储每个具有C_ID的项目，而C_ID将存储在（StationaryOrders）中该表不是唯一的，因为C_ID将与该C_ID所属的每个项目重复。

我想通过C_ID显示每个订单，每个客户的每个订单都将使用单独的表格显示。

$sql=mysqli_query($link, "SELECT Item, Personal, Department, Quantity, Color FROM StationaryOrders, StationaryCustomersInfo WHERE StationaryCustomersInfo.C_ID = StationaryOrders.C_ID");

?>
<table align="center" border='3' style="width:60%; line-height:30px; border-color: #020B58;">
      <tr>
      <th>Items</th>
      <th>Personal</th>
      <th>Department</th>
      <th>Quantity</th>
      <th>Color</th>
      </tr>

          <?php
    if($sql){

           while($row=mysqli_fetch_assoc($sql)){
               ?>

      <tr>
      <td style="text-align:center"><?php echo $row['Item']; ?></td>
      <td style="text-align:center"><?php echo $row['Personal']; ?></td>
      <td style="text-align:center"><?php echo $row['Department']; ?></td>
      <td style="text-align:center"><?php echo $row['Quantity']; ?></td>
      <td style="text-align:center"><?php echo $row['Color']; ?></td>
      </tr>
    <?php
          }
    }

    ?>

</table>

我希望用单独的表格显示每个客户的订单，并且按钮属于该表格。

Answer 1

这可以通过在查询中添加C_ID并按C_ID对结果进行排序来完成。然后，在php中，您可以检查以前的抓取C_ID是否与当前抓取相同。

例如：

// Let's factorise the building of the <table> header there to avoid duplication in code
function ShowTableHeader($cid)
{
    ?>
<table align="center" border='3' style="width:60%; line-height:30px; border-color: #020B58;">
      <caption>Orders of user <?php echo $cid; ?> : </caption>
      <tr>
      <th>Items</th>
      <th>Personal</th>
      <th>Department</th>
      <th>Quantity</th>
      <th>Color</th>
      </tr>
    <?php
}

$query = "SELECT sci.C_ID, "
        .       "Item, "
        .       "Personal, "
        .       "Department, "
        .       "Quantity, "
        .       "Color "
        ."FROM StationaryOrders so "
        ."LEFT JOIN StationaryCustomersInfo sci "
        ."ON sci.C_ID = so.C_ID "
        ."ORDER BY sci.C_ID";

$sql = mysqli_query($link, $query);
if ($sql)
{
    if ($row=mysqli_fetch_assoc($sql))
    {
        // initialize the first C_ID for the first result
        $previousCID = $row['C_ID'];
        ShowTableHeader($previousCID);
        do
        {
            // different C_ID than before ? Let's build a new <table>
            if ($previousCID != $row['C_ID'])
            {
                echo "</table>";
                $previousCID = $row['C_ID'];
                ShowTableHeader($previousCID);
            }
            ?>
      <tr>
      <td style="text-align:center"><?php echo $row['Item']; ?></td>
      <td style="text-align:center"><?php echo $row['Personal']; ?></td>
      <td style="text-align:center"><?php echo $row['Department']; ?></td>
      <td style="text-align:center"><?php echo $row['Quantity']; ?></td>
      <td style="text-align:center"><?php echo $row['Color']; ?></td>
      </tr>
    <?php
        } while ($row=mysqli_fetch_assoc($sql));
        echo "</table>";
    }
}

如何在单独的表格中显示每个相似的行？

1 个答案: