Question

这两个函数在lamba函数中不能用作args 正在计算糖果的价格
def mysweets():
    b = v.get( ) # get the value of v set
    cost=int(mysweets_price_list[b]) #price_display
    print(cost)



def quantity_sweets():
    q = int(spinbox1.get())
    print(q)

price = lambda b, q : b * q # final price to be displayed in myLabel_3

print(price(b, q))
我已经尝试过嵌套函数，但是它们无法正常工作，请帮助任何人

from tkinter import *

myGui = Tk()
myGui.geometry('450x450+200+200')
myGui.title('Auto Sweet Dispenser')

price_display = ""
b = 0
#a = 0
q = 0
mysweets_price_list = {1 :9.00,
                      2 :7.50,
                      } # dict for the sweet prices

def mysweets():
    b = v.get( ) # get the value of v set
    cost=int(mysweets_price_list[b]) #price_display
    print(cost)



def quantity_sweets():
    q = int(spinbox1.get())
    print(q)

price = lambda b, q : b * q # final price to be displayed in myLabel_3

print(price(b, q))


v =IntVar()
price =IntVar()
v.set(1)

myLabel = Label(myGui,text = 'Choose your sweets',font = 14, fg ='brown').place(x=140,y=55)#grid(row=3,column=10,sticky = 'e')

myRadio_1 = Radiobutton(myGui,text = 'Mints',variable = v, value = 1, command = mysweets).place(x= 160, y = 100)
myRadio_2 = Radiobutton(myGui,text = 'Nut log',variable = v, value = 2, command = mysweets).place(x= 160, y = 120)


myLabel_2 = Label(myGui,text = 'Select Quantity',font = 12, fg ='brown').place(x=160,y=160)#grid(row=3,column=10,sticky = 'e')

myLabel_3 = Label(myGui,textvariable = price ,font = "Times 14 bold",width = 14, fg ='white', bg= 'blue' ,relief = RAISED).place(x=160,y=220)#grid(row=3,column=10,sticky = 'e')


spinbox1 = Spinbox(myGui,from_=1,to = 6,command = quantity_sweets, state = NORMAL)
spinbox1.place(x=160,y=180)#



myGui.mainloop()

该代码有效，除了价格未显示为lambda 功能不起作用。

Answer 1

您不需要在这里使用lambda（通常来说lambda应该非常少见）。您只需要一个函数即可获取所有数据，进行计算并更新Label。像这样：

from tkinter import *

myGui = Tk()
myGui.geometry('450x450+200+200')
myGui.title('Auto Sweet Dispenser')

mysweets_price_list = {1 :9.00,
                      2 :7.50,
                      } # dict for the sweet prices

def calculate():
    b = v.get( ) # get the value of v set
    cost=mysweets_price_list[b] #price

    q = int(spinbox1.get()) # get quantity.

    final_price = cost * q # final price to be displayed
    price.set(final_price)

v =IntVar(value=1) # set initial value to 1
price = IntVar()

Label(myGui,text = 'Choose your sweets',font = 14, fg ='brown').place(x=140,y=55)#grid(row=3,column=10,sticky = 'e')

Radiobutton(myGui,text = 'Mints',variable = v, value = 1, command = calculate).place(x= 160, y = 100)
Radiobutton(myGui,text = 'Nut log',variable = v, value = 2, command = calculate).place(x= 160, y = 120)

Label(myGui,text = 'Select Quantity',font = 12, fg ='brown').place(x=160,y=160)#grid(row=3,column=10,sticky = 'e')

Label(myGui,textvariable = price ,font = "Times 14 bold",width = 14, fg ='white', bg= 'blue' ,relief = RAISED).place(x=160,y=220)#grid(row=3,column=10,sticky = 'e')

spinbox1 = Spinbox(myGui,from_=1,to = 6,command = calculate, state = NORMAL)
spinbox1.place(x=160,y=180)

calculate() # do the calculation at boot
myGui.mainloop()

此外，知道如果您进行name = Widget().place()，则名称将设置为None，并且毫无用处，这一点非常重要。您需要

name = Widget()
name.grid() # or pack() or place()

或

Widget().grid() # or pack() or place()

不要混用这两种样式！ 2行样式更好，并且通常使用。

在Lambda函数中将多个函数作为参数传递不起作用

1 个答案: