Question

我有表users，deposits和withdrawals，我正在尝试编写查询以获取用户 balance 。

desposits

id  | amount  | user_id
1   | 4000    | 1
2   | 3500    | 1

withdrawals

id  | amount  | user_id
1   | 4000    | 1

这是我当前的查询：

SELECT u.id AS user_id,
COALESCE(SUM(d.amount), 0) AS sum_deposits,
COALESCE(SUM(w.amount), 0) AS sum_withdrawals
FROM users AS u
WHERE u.id = 1
LEFT JOIN deposits AS d ON u.id = d.user_id
LEFT JOIN withdrawals AS w ON u.id = w.user_id
GROUP BY u.id

我得到的结果是-500，我认为这是因为提款计算了两次，例如：SUM(4000, 3500) - SUM(4000, 4000) = -500

如何解决我的查询？

Answer 1

您应该使用子查询

SELECT u.id AS user_id,
  (SELECT COALESCE(SUM(d.amount), 0) 
     FROM deposits AS d WHERE u.id = d.user_id) AS sum_deposits,
  (SELECT COALESCE(SUM(w.amount), 0) 
     FROM withdrawals AS w WHERE u.id = w.user_id) AS sum_withdrawals
FROM users AS u
WHERE u.id = 1

Answer 2

我会union all而不是加入：

select user_id, 
       sum(case when trans_type = 'Deposit' then amount end) as sum_deposit,
       sum(case when trans_type = 'Withdrawal' then amount *-1 end) as sum_Withdrawal,
       sum(amount) as net_amount
from
  (
  select user_id, amount, 'Deposit' as trans_type
  from Deposits
  union all
  select user_id, amount * -1, 'Withdrawal'
  from Withdrawals
  ) t1
group by user_id

Answer 3

试试这个-

SELECT A.user_id, A.amount - B.amount Balance
FROM (
    SELECT user_id,SUM(amount) amount
    FROM desposits
    GROUP BY user_id
) A
LEFT JOIN (
    SELECT user_id,SUM(amount) amount
    FROM withdrawals 
    GROUP BY user_id
)B ON A.User_id = B.user_id

SQL：来自两个联接表的值的总和

3 个答案: