Question

如何在python的嵌套列表中附加alpha值？

nested_list = [['72010', 'PHARMACY', '-IV', 'FLUIDS', '7.95'], ['TOTAL', 
'HOSPITAL', 'CHARGES', '6,720.92'],['PJ72010', 'WORD',  'FLUIDS', 
'7.95']]



Expected_output:
[['72010', 'PHARMACY -IV FLUIDS', '7.95'], ['TOTAL HOSPITAL CHARGES', '6,720.92'],['PJ72010', 'WORD  FLUIDS', '7.95']]

Answer 1

如果创建定义单词含义的函数，则可以使用itertools.groupby()对该函数进行分组。然后，您可以附加join()的结果，也可以附加extend()，具体取决于它是一组单词数。

我从您的示例中推断出，您是从没有数字的任何事物定义单词，但是您可以根据需要调整函数：

from itertools import groupby

# it's a word if it has no numerics
def word(s):
    return not any(c.isnumeric() for c in s)

def groupwords(s):
    sub = []
    for isword, v in groupby(s, key = word):
        if isword:
            sub.append(" ".join(v))
        else:
            sub.extend(v)
    return sub

res =[groupwords(l) for l in nested_list]
res

结果：

[['72010', 'PHARMACY -IV FLUIDS', '7.95'],
 ['TOTAL HOSPITAL CHARGES', '6,720.92'],
 ['PJ72010', 'WORD FLUIDS', '7.95']]

Answer 2

浏览每个嵌套列表。检查该列表的每个元素。如果它是完整的alpha den，则将其附加到临时变量中。找到数字后，将临时数和数字都追加。代码：

nested_list = [['72010', 'PHARMACY', '-IV', 'FLUIDS', '7.95'], ['TOTAL', 
'HOSPITAL', 'CHARGES', '6,720.92'],['PJ72010', 'WORD',  'FLUIDS', 
'7.95']]

def isAlpha(temp):
   for i in temp:
      if i>='0' and i<='9':
         return 0
   return 1


isAlpha("abul")
anser_list=[]
for  i in nested_list:
   nested_list=[]
   temp=""
   for j in i:
      if isAlpha(j)==1:
         if len(temp)>0:
            temp+=" "
         temp+=j
      else:
         if len(temp)>0:
            nested_list.append(temp)
            temp=""
         nested_list.append(j)
   if len(temp)>0:
      nested_list.append(temp)
   anser_list.append(nested_list)

for  i in anser_list:
   print(i)

输出将是：

['72010', 'PHARMACY -IV FLUIDS', '7.95']
['TOTAL HOSPITAL CHARGES', '6,720.92']
['PJ72010', 'WORD FLUIDS', '7.95']

如何在python的嵌套列表中附加alpha值？

2 个答案: