Question

我在web.php中声明了两条laravel路由，但是面临404错误。

我想访问控制器中的路由参数值，并且基于此选择，我需要基于参数执行一些处理。

我的web.php代码

public function validationrequest(Request $request)
{

$password = $request->header('Password');
$username = $request->header('Username');

    $msisdn=$request->msisdn;
    $useresponse=$request->userresponse;
    $useroption=$request->useroption;
    $hash=$request->hash;
    $hash_key="CIA152515276585";

    $data=$msisdn.$useresponse.$useroption.$hash_key;
    $hashed = hash('sha512',$data);

if($username=="ngfs" && $password=="jfgd")
{ 
      if($hashed==$hash)
      {
          //implemetation 
         $ref_id=self::gen_uuid();
         $cus_name="greatB";
         $total_amount=456;
         $statuscode="00";
     $statusMsg = "Successful";
         $message="Testing";
     $data = $total_amount.$statuscode.$statusMsg.$message.$hash_key;
     $hashed = hash('sha512',$data);

        $games = BBVN::where('game_code',$useresponse)->get(); 
            User_Response::create([
                'game_code'     =>  $games->game_code,
                'answer'        =>  $useroption,
                'msisdn'        =>  $msisdn
            ]); 

        return response()->json([
         'amount'=>$total_amount,
          'statusCode'=>$statuscode,
           'statusMessage'=>$statusMsg,
            'message'=>$message,
              'hash'=>$hashed
            ]);
}else
{
      $notification1 = new NotificationLog();
      $notification1->amount = $total_amount;
      $notification1->msisdn = $msisdn;;
      $notification1->error_message = "Invalid haskey";
      $notification1->error_code = "99";
 return response(['errorMsg' =>"99", 'description' =>"Invalid haskey"]);
}
}
else
{
      $notification2 = new NotificationLog();
      $notification2->amount = $total_amount;
      $notification2->msisdn = $msisdn;;
      $notification2->error_message = "Invalid haskey";
      $notification2->error_code = "99";    
 return response(['errorMsg' =>"99", 'description' =>"Invalid username and password"]);
}         
}

我的控制器代码

Route::group(
        ['namespace' => 'Admin', 'prefix' => 'admin', 'as' => 'admin.', 'middleware' => ['role:admin']],
        function () {
Route::get('transaction-verified/{user-id}/{tran-id}',['uses' => 'ForgotPassTranVerifyController@transaction_verified'])->name('transaction_verified');

});

这是我叫路线的方式，

public function transaction_verified($id,$tran_id)
    {
        $user = User::find($id);
        if($user)
        {
            $user->status = 'active';
            $user->save();
            $response = $this->broker()->sendResetLink(
                $user->email
            );
            echo'<pre>'; print_r($response); exit;
            $transaction = ForgotPassFineTransaction::find($tran_id);
            if($transaction)
            {
                $transaction->status = 'valid';
                $transaction->save();
            }
            $this->message = true;
            return redirect(route('admin.transaction-verify'));
        }

我想访问路线参数，并且根据参数需要完成一些任务。但是我正面临404错误。我无法弄清楚出了什么问题？

Answer 1

我可以看到一些问题：

根据the Laravel docs，路由参数：

...应该由字母字符组成，并且不能包含-字符。代替使用-字符，而使用下划线（_）。

因此，像{user-id}和{tran-id}这样的参数名称将不起作用。将它们更改为（例如）{user_id}和{tran_id}。
您的路线定义在URL中包含了这两个参数：
```
.../{user-id}/{tran-id}...
```
使用route()生成路线时，必须给它提供两个具有相同名称的参数。但是您的代码给了它一个id：
```
...['id'=> $row->id, 'tran-id'=> $row->tran_id]...
```
您需要将id更改为user-id，或考虑上述问题user_id。

Laravel路由无法使用参数

1 个答案: