Question

我正在尝试使用子图，但收到一条错误消息，我不知道如何纠正。

（此外，由于仅w的值发生变化，有没有比连续十次说“ cos（stuff * t”）更紧凑的方式来编写此代码了？）

我当前的代码是

clear all
clc

t = 0:0.001:40;
% there are 10 values of w to show, so make a 2x5 grid to show them all via
% subplot (2,5, blank)

x1=cos(pi/16*t);
x2=cos(pi/8*t);
x3=cos(pi/4*t);
x4=cos(pi/2*t);
x5=cos(pi*t);
x6=cos(15*pi/8*t);
x7=cos(2*pi*t);
x8=cos(5*pi/2*t);
x9=cos(3*pi*t);
x10=cos(4*pi*t);

subplot(2,5,x1), plot(t,x,1), subplot(2,5,x2), plot(t,x,2), subplot(2,5,x3), 
plot(t,x,3), subplot(2,5,x4), plot(t,x,4), subplot(2,5,x5), plot(t,x,5), 
subplot(2,5,x6), plot(t,x,6), subplot(2,5,x7), plot(t,x,7), subplot(2,5,x8), 
plot(t,x,8), subplot(2,5,x9), plot(t,x,9), subplot(2,5,x10), plot(t,x,10);



%Error using subplot (line 330);

%Illegal plot number;

%Error in (line 19);
%subplot(2,5,x1), plot(t,x,1);

Answer 1

您刚刚混合了services: my-service: image: ${PYTHON_IMAGE}:${PY_VERSION}和plot的参数。

阅读subplot文档。

这是您的代码的更正版本：

subplot

以下是使用for循环的方法：

clear all
clc

t = 0:0.001:40;
% there are 10 values of w to show, so make a 2x5 grid to show them all via
% subplot (2,5, blank)

x1=cos(pi/16*t);
x2=cos(pi/8*t);
x3=cos(pi/4*t);
x4=cos(pi/2*t);
x5=cos(pi*t);
x6=cos(15*pi/8*t);
x7=cos(2*pi*t);
x8=cos(5*pi/2*t);
x9=cos(3*pi*t);
x10=cos(4*pi*t);

subplot(2,5,1);
plot(t,x1);
subplot(2,5,2);
plot(t,x2);
subplot(2,5,3);
plot(t,x3);
subplot(2,5,4);
plot(t,x4);
subplot(2,5,5);
plot(t,x5);
subplot(2,5,6);
plot(t,x6);
subplot(2,5,7);
plot(t,x7);
subplot(2,5,8);
plot(t,x8);
subplot(2,5,9);
plot(t,x9);
subplot(2,5,10);
plot(t,x10);

您甚至可以在没有第一个clear all clc t = 0:0.001:40; % there are 10 values of w to show, so make a 2x5 grid to show them all via % subplot (2,5, blank) W = [1/16, 1/8, 1/4, 1/2, 1, 15/8, 2, 5/2, 3, 4]*pi; %X Replaces x1 to x10 X = zeros(10, length(t)); %Fill X with 10 rows (X(1, :) matches x1, X(2, :) matches x2...) for i = 1:10 X(i, :) = cos(W(i)*t); end %Plot using a for loop for i = 1:10 subplot(2,5,i); plot(t, X(i, :)); end循环的情况下进行操作：

for

尝试使用子图时出现非法图错误

1 个答案: